The value of x is 15° and the type of quadrilateral is a rhombus.
<h3>
Quadrilateral</h3>
- A quadrilateral is a polygon that has four sides.
- The sum of all angles of a quadrilateral is 360°.
Here, we are given,
m∠A = (7x)◦, m∠B = (4x + 5)◦, m∠C =(6x + 15)◦, m∠D = (6x −5)◦
So, we will have
7x+4x+5+6x+15+6x-5=360°
23x+15°=360°
23x=345°
x=345°/23°
x=15°
Hence, the angles of the quadrilateral are:
m∠A = (7x)◦=105°,
m∠B = (4x + 5)◦ =65°
m∠C =105°
m∠D = (6x −5)◦ =85°
Since the diagonal bisects ∠B and ∠D, we get that the quadrilateral is a rhombus.
To learn more about rhombus refer to:
brainly.com/question/27870968
#SPJ10
Answer:
1
Step-by-step explanation:
None of these numbers are alike terms so the only number left is 1.
Answer:
Step-by-step explanation:
11: 16
12: 43.2
13: 1/18
Answer:
A. -1 1/3
Step-by-step explanation:
I am assuming you want to find the number that is farthest to the right of all 4 possible choices. In that case, the bigger the negative number, the farther left it is on the number line. The smaller the negative number, the farther right it is on the number line.
Answer:
h≤-19/6
Step-by-step explanation:
10 2/3 + 2h ≤ 4 1/3?
-10 2/3 -10 2/3
2h/-19/3≤ -19/3/-19/3
h≤-19/6