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gladu [14]
3 years ago
11

What is 2^ + 2^? (^ means squared for those who can't math.)

Mathematics
1 answer:
Andrei [34K]3 years ago
7 0

Answer:

2^2 + 2^2 = 8

You might be interested in
A circle has a diameter of 6 centimeters what is the approximate area of the circle​
KiRa [710]

Answer:

28.26 cm^{2}

Step-by-step explanation:

The radius is half of the diameter. 6/2 = 3, so the radius of this circle is 3 cm.

The formula for the area of a circle is: πr^{2}

Plugging 3 into the radius, we have:

3^{2} × π =

9 × π

We can round π to 3.14

9 × 3.14 = 28.26

7 0
2 years ago
If the coordinates of the endpoints of a diameter of the circle are​ known, the equation of a circle can be found.​ First, find
Evgesh-ka [11]

Answer:

The equation of the circle is (x+3)^2+(y-5)^2 = 17

Step-by-step explanation:

The complete question is

If the coordinates of the endpoints of a diameter of the circle are​ known, the equation of a circle can be found.​ First, find the midpoint of the​ diameter, which is the center of the circle. Then find the​ radius, which is the distance from the center to either endpoint of the diameter. Finally use the​ center-radius form to find the equation.

Find the center-radius  form of the circle having the points (1,4) and (-7,6) as the endpoints of a diameter.

Consider that, if both points are the endpoints of a diameter, the center of the circle is the point that is exactly in the middle of the two points (that is, the point whose distance to each point is equal). Given points (a,b) and (c,d), by using the distance formula, you can check that the middle point is the average of the coordinates. Hence, the center of the circle is given by

(\frac{1-7}{2}, \frac{4+6}{2}) = (-3,5).

We will find the radius. Recall that the radius of the circle is the distance from one point of the circle to the center. Recall that the distance between points (a,b) and (c,d) is given by \sqrt[]{(a-c)^2+(b-d)^2}. So, let us use (1,4) to calculate the radius.

r = \sqrt[]{(1-(-3))^2+(4-5)^2} = \sqrt[]{17}.

REcall that given a point (x_0,y_0). The equation of a circle centered at the point (x_0,y_0) is

(x-x_0)^2+(y-y_0)^2 = r^2

In our case, (x_0,y_0)=(-3,5) and r=\sqrt[]{17}. Then, the equation is

(x-(-3))^2+(y-5)^2 = (x+3)^2+(y-5)^2 = 17

4 0
3 years ago
$350, 6.2%, 3 years plzz help
KIM [24]

Answer:

not much info

Step-by-step explanation:

8 0
3 years ago
Consider isosceles ΔXYZ.
Rom4ik [11]

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The length of the legs XY and YZ is equal to 39 units.

<h3>What is a triangle?</h3>

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angles of a triangle is always equal to 180°. An isosceles triangle has two sides out of three equal.

A.) The value of n can be found by equating XY and XZ together,

XY = XZ

9n + 12 = 15n - 6

12 + 6 = 15n - 9n

18 = 6n

n = 3

Hence, the value of n is 3.

The length of different legs of the triangle is,

B.) XY = 9n + 12 = 9(3) + 12 = 27 + 12 = 39

C.) YZ = 15n - 6 = 15(3) - 6 = 45 - 6 = 39

Hence, the length of the legs XY and YZ is equal to 39 units.

Learn more about Triangle:

brainly.com/question/2773823

#SPJ1

6 0
1 year ago
Picture provided help!
weqwewe [10]

Answer:

A -60i - 14j

Step-by-step explanation:

u = -9i + 8j

v = 7i + 5j

2u = 2(-9i + 8j) = -18i + 16j

6v = 6(7i + 5j) = 42i + 30j

2u - 6v

(-18i + 16j) - (42i + 30j)

(-18i - 42i) + (16j-30j)

-60i - 14j

5 0
3 years ago
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