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Elan Coil [88]
3 years ago
8

Writing algebraic expressions for: A number decreased by 5 is 12

Mathematics
1 answer:
snow_lady [41]3 years ago
6 0

Answer:

x-5=12

hope this helps

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What is the middle product of (-2x + 1)(-3x - 5)? <br><br><br> 7x<br><br> -3x<br><br> -7x
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Cube root(8+ 3 root 21)+ cube root (8-3 root 21)
krok68 [10]

Answer:

  • \sqrt[3]{8+3\sqrt{21} } + \sqrt[3]{8-3\sqrt{21} } = 1

Step-by-step explanation:

<h3>Given</h3>
  • \sqrt[3]{8+3\sqrt{21} } + \sqrt[3]{8-3\sqrt{21} }
<h3>To find </h3>
  • The value of the expression
<h3>Solution</h3>

<u>Let's rewrite the given as:</u>

  • <u />\sqrt[3]{3\sqrt{21} + 8} - \sqrt[3]{3\sqrt{21} - 8}

<u>Let the value is m and the expressions under 3rd roots are a and b, then we have </u>

  • a = 3√21 + 8, b = 3√21 - 8
  • m = ∛a - ∛b

<u>Cube the both sides:</u>

  • m³ = (∛a - ∛b)³
  • m³ = a - b - 3\sqrt[3]{a^2b} + 3\sqrt[3]{ab^2}

<u>Simplify in bits:</u>

  • a - b = 3√21 + 8 - 3√21 + 8 = 16
  • ab = (3√21 + 8)(3√21 - 8) = 9*21 - 64 = 125
  • ∛ab = ∛125 = 5

<u>So the expression becomes:</u>

  • m³ = 16 - 3\sqrt[3]{125a} + \sqrt[3]{125b}
  • m³ = 16 - 15∛a + 15∛b
  • m³ = 16 - 15(∛a - ∛b)
  • m³ = 16 - 15m

<u>Solve for m:</u>

  • m³ + 15m - 16 = 0
  • m³ - 1 + 15m - 15 = 0
  • (m - 1)(m² + m + 1) + 15(m - 1) = 0
  • (m - 1)(m² + m + 16) = 0
  • m - 1 = 0, m² + m + 16 = 0
  • m = 1 is the only real root, the quadratic equation has no real roots

The answer is 1

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