Answer:- 0.143 M
Solution:- HCl and NaOH reacts in 1:1 mol ratio as shown in the below reaction:
![HCl(aq)+NaOH(aq)\rightleftharpoons NaCl(aq)+H_2O(l)](https://tex.z-dn.net/?f=HCl%28aq%29%2BNaOH%28aq%29%5Crightleftharpoons%20NaCl%28aq%29%2BH_2O%28l%29)
Let's calculate the initial moles of HCl and the moles of NaOH added to it:
![250.mL(\frac{1L}{1000mL})(\frac{0.3molHCl}{1L})](https://tex.z-dn.net/?f=250.mL%28%5Cfrac%7B1L%7D%7B1000mL%7D%29%28%5Cfrac%7B0.3molHCl%7D%7B1L%7D%29)
= 0.075 mol HCl
![100.mL(\frac{1L}{1000mL})(\frac{0.25molNaOH}{1L})](https://tex.z-dn.net/?f=100.mL%28%5Cfrac%7B1L%7D%7B1000mL%7D%29%28%5Cfrac%7B0.25molNaOH%7D%7B1L%7D%29)
= 0.025 mol NaOH
Since they react in 1:1 mol ratio, 0.025 mol of NaOH will react with 0.025 moles of HCl.
Remaining moles of HCl = 0.075 - 0.025 = 0.050
Total volume of the resulting solution = 0.250 L + 0.100 L = 0.350 L
So, the concentration of HCl in the resulting solution = ![\frac{0.050mol}{0.350L}](https://tex.z-dn.net/?f=%5Cfrac%7B0.050mol%7D%7B0.350L%7D)
= 0.143 M
Hence, the concentration of HCl acid in the resulting solution is 0.143 M.
Answer:
its D I'm pretty sure because it's from high heat/pressure
Here's link to the answer:
bit.
ly/3a8Nt8n