Answer: There are 0.056 moles present in 3.45 g of
.
Explanation:
Given : Mass = 3.45 g
Moles is the mass of substance divided by its molar mass.
Hence, moles of
(molar mass = 61.98 g/mol) is as follows.

Thus, we can conclude that there are 0.056 moles present in 3.45 g of
.
Answer:

Explanation:
We are given the compound: Cs₃PO₄
According to the formula, 1 mole of cesium phosphate contains 3 moles of cesium, 1 mole of phosphate, and 4 moles of oxygen.
Therefore, there are 3 moles of cesium for 1 mole of cesium phosphate.

We want to calculate the moles of cesium in 3 moles of cesium phosphate, so we multiply the ratio by 3.


3 moles of cesium phosphate contains <u>9 moles of cesium.</u>
Answer:
True
Explanation:
*For polar and associated substances, methods based on four should be used four or more parameters, like analytical equation of state
*The term "analytical equation of state" implies that the function
It contains powers of v not greater than four.
*Most expressions are of the cubic type and are grouped into
the so-called cubic equations of state.
*Cubic EoS calls are very popular in simulation of
processes due to its robustness and its simple extension to mixtures.
*They are based on the van der Waals state equation of more than
100 years.