How do I do this question on a calculator (as shown below) note the calculator only can write out equations

Liam's breakfast was an egg and cheese biscuit with a carton of milk. He spent a total of $5.65. Finn spent $7.65 on an egg and

ruslelena [56]

Answer:

An egg and cheese biscuit was $3.65.

Step-by-step explanation:

Liam's breakfast was:

$P = E + C + M$

Where:

P: total price

E: egg

C: cheese biscuit

M: carton of milk

$P = E + C + M$

$5.65 = E + C + M$ (1)

Now, Finn's breakfast was:

$P = E + C + 2*M$

$7.65 = E + C + 2*M$ (2)

By subtracting equation (2) from (1) we have:

$7.65 - 5.65 = 2M - M$

$M = 2$

Hence, the price of a carton of milk is $2, so by entering this value into equation (1) we can find the price of an egg and cheese biscuit:

$5.65 = E + C + M$

$5.65 - 2 = E + C$

$E + C = 3.65$

Therefore, an egg and cheese biscuit was $3.65.

I hope it helps you!

7 0

3 years ago

1. How many juniors like to watch track?

SSSSS [86.1K]

Answer:

1. 3

2. 23

3. 50

4. 26%

5. 24%

Step-by-step explanation:

3 0

2 years ago

abel drew some triangles.his drawing had 21 vertices. how many triangles did he draw?write a division equation to answer the que

Vilka [71]

Triangles have 3 vertices. The total is 21 vertices. 21 / 3 = 7. He drew 7 triangles.

3 0

3 years ago

In the data set below, which of these points is most likely and outlier?

shusha [124]

<h2>Answer:</h2>

Option: D is the correct answer.

D. (2,54)

<h2>Step-by-step explanation:</h2>

We know that an outlier of a data set is the value that stands out of the rest of the data point i.e. either it is a too high value or a too low value as compared to other data points.

Here we are given a set of data points as:

(2,54)

(4,7)

(6, 9)

(8,12)

(10,15)

Hence, we see that the output values i.e. 7 in (4,7) ; 9 in (6,9) ; 12 in (8,12) and 15 in (10,15) are closely related.

Hence, the data point that is an outlier is:

(2,54)

(As 54 is a much high value as compared to other)

5 0

3 years ago

Based on past experience, a telemarketing firm has found that calls to prospective customers take an average of 2.0 minutes, wit

xenn [34]

Answer: Our required probability would be 0.9641.

Step-by-step explanation:

Since we have given that

Number of hours he works a day = 8

So, Number of minutes he worked in a day = $8\times 60=480\ minutes$

Number of calls = 220

So, Average $=\bar{x}=\dfrac{480}{220}=2.18\ minutes$

Standard deviation $=s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.5}{\sqrt{220}}=0.10$

Mean = μ = 2.0 minutes

Standard deviation = σ = 1.5 minutes

Using the normal distribution, we get that

$z=\dfrac{\bar{x}-\mu}{s}\\\\z=\dfrac{2.18-2.0}{0.10}\\\\z=1.8$

So, the probability that Albert will meet or exceed his quota would be

$P(X\leq 2.18)=P(z\leq 1.8)=0.9641$

Hence, our required probability would be 0.9641.

6 0

3 years ago