A fathers age = three less than two times the son's age can be writtens as: f=2s-3. Since the difference in their age, f-s=30, we can solve for s and find that s=f-30. plugging this in to the first equation, we get f=2(f-30)-3 = 2f-60-3 =2f-63
f=2f-64
solvinh for f yields,
f=64
if thr father is 64, the son's age is therfore 64-30=34
Let the two number be x and y.
x+y=-1......i
2x+4y=-10.....ii
solving the simultaneous equation we have:
from equation i, making x the subject we get:
x=-1-y........iii
substituting iii in ii we get:
2(-1-y)+4y=-10
-2-2y+4y=-10
2y=-10+2
2y=-8
y=-8/2=-4
substituting the value of y in iii we get:
x=-1-(-4)
x=-1+4
x=3
therefore the first number is 3 and the second number is -4
Answer:
it is very very tall hfhfhfudddhehhd
Step-by-step explanation:
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