Actually I can help you in three of them as the number "3" is not confined between the arrays ND and NE

So:
It would be
angle END
or
angle DNE
or
angle N

6 0

3 years ago

Find (a) the slope of the curve at the given point p, and (b) an equation of the tangent line at p. y=−2−9x2; p(2,−38)

Neporo4naja [7]

Answer:

a) -36

b) y = -36x +34

Step-by-step explanation:

a) The slope is found using the derivative of the function.

f'(x) = dy/dx = 0 -9(2x) = -18x

Then at x=2, the slope is ...

f'(2) = -18·2 = -36

___

b) The point-slope form of the equation can be written as ...

y = -36(x -2) -38

Simplifying to slope-intercept form, we get ...

y = -36x +34

6 0

3 years ago

What are the solution

AleksandrR [38]

Answer:

Step-by-step explanation:

We can get two equations from the inequality:

$3x+2>9\\3x+2>-9$

We just need to simplify both equations to get our answers:

$3x+2>9\\3x>7\\x>\frac{7}{3}$

$3x+2>-9\\3x>-11\\x>\frac{-11}{3}$

The two answers we get are:

$x\frac{7}{3}$

Which is also B.

3 0

2 years ago