All categories

3 years ago

How much meters are in how many cm

Mathematics

2 answers:

Alborosie3 years ago

4 0

10 mm = 1 cm
100 cm = 1 m
1000 m = 1 km

0.001 km = 1 m
0.01 m = 1 cm
0.1 cm = 1 mm

Aliun [14]3 years ago

3 0

1000cm...........,..

You might be interested in

Please help me. (20 points)

alexandr402 [8]

Hello from MrBillDoesMath!

Answer:

Discussion:

A plane triangle has 180 degrees. Using this in the diagram gives

x + 81 + angle BAC = 180 (***)

(The diagram is a bit fuzzy but I think the above numbers are accurate)

The diagram also shows that (156 + angle BAC )= 180 as a straight line has 180 degrees. So

angle BAC = 180 - 156 = 24

Substituting this in (***) above gives

x + 81 + 24 = 180 =>

x + 105 = 180 => (as 81 + 24 = 105)

x = 180 107 = 75

Check: Does

x + 81 + angle BAC = 180 ?

75 + 81 + 24 = 180. Yes

Thank you,

MrB

7 0

2 years ago

P - 3.1(6) =-2.1(2) what is the answer and explained

harina [27]

Answer:

P = 14.4

Step-by-step explanation:

Multiply out -3.1(6) and -2.1(2).

P - 18.6 = - 4.2

Add - 18.6 to the other side of the Equation.

P = 14.4

4 0

2 years ago

Find the area of a rectangle with a base 7 yard and height 4 feet <br><br><br> Please help

Tanya [424]

Answer:

84 feet

Step-by-step explanation:

take the 7 yards into feel that is 21

times that buy 4 feet and you get 84 feet

6 0

2 years ago

Please answer all 3 questions

blsea [12.9K]

Answer:

x = 30°
DB = 26
AD = BC = AB = DC = 7

Step-by-step explanation:

<em>Diagonals of a square are congruent and perpendicular and bisect each other</em>

m∠AEB = 3x

m∠AEB = 90°

3x = 90° ⇒ x = 30°

AE = 3x - 2

EC = 2x + 3

AE = EC
3x - 2 = 2x + 3
3x - 2x = 3 + 2
x = 5

DB = EC = 2(AE) = 2(3*5 - 2) = 2(13) = 26

<u>AD and BC are the sides, which are equal</u>

2x - 1 = 5x - 13
5x - 2x = 13 - 1
3x = 12
x = 4

AD = BC = AB = DC = 2*4 - 1 = 7

7 0

2 years ago

Read 2 more answers

An equation of an ellipse is given. y2 = 1 − 3x2 (a) Find the vertices, foci, and eccentricity of the ellipse. vertex (x, y) = (

oksian1 [2.3K]

Answer:

Step-by-step explanation:

Given

$y^2=1-3x^2$

$3x^2+y^2=1$

$\frac{x^2}{(\frac{1}{\sqrt{3}})^2}+\frac{y^2}{1}=1$

therefore it is a vertical ellipse

thus a=1

$b=\frac{1}{\sqrt{3}}$

eccentricity of Ellipse

$e^2=1-\frac{b^2}{a^2}$

$e^2=1-\frac{1}{(\sqrt{3})^2}$

$e^2=1-\frac{1}{3}$

$e^2=\frac{2}{3}$

$e=\sqrt{\frac{2}{3}}$

Focii are $(0,ae)$ and $(0,-ae)$

$ae=1\times \sqrt{\frac{2}{3}}$

thus focii are $(0,\sqrt{\frac{2}{3}})$ & $(0,-\sqrt{\frac{2}{3}})$

(b) Length of major axis $=2a=2\times 1$

length of minor axis $=2b=2\times \sqrt{\frac{2}{3}}=2\cdot \sqrt{\frac{2}{3}}$

8 0

3 years ago