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FromTheMoon [43]
2 years ago
12

Helppp! idk why its needs to be 20 charactes so i wrote this

Mathematics
2 answers:
denis-greek [22]2 years ago
7 0
I’m sure this should be 18?
marin [14]2 years ago
6 0
This should be 1.35, sorry if it’s wrong
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There are 14 lirts to every10 Rews,You Have 100lirts how many rews are there?
netineya [11]

Answer:

the ratio of 14:10 is equivalent to 100:71

if there are 100 lirts, there are 71 rews

:) hope this helped have a great day

5 0
3 years ago
**NEED HELP???!!! ****
Nezavi [6.7K]
210/20=10.5 per hour
So
2000/10.5=190 hours
3 0
3 years ago
Find the percent increase. Round to the nearest percent
Dmitrij [34]
The percent increase is 18.18 repeating
6 0
2 years ago
Write each fraction as a percent 2 __ 10
fgiga [73]
2_10 i'm guessing means 2/10, so in percentage, it would be 20%
5 0
3 years ago
Assume that when adults with smartphones are randomly​ selected, 63​% use them in meetings or classes. If 7 adult smartphone
nlexa [21]

Answer:

5.78% probability that exactly 2 of them use their smartphones in meetings or classes.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they use their smarthphone in meetings or classes, or they do not. The probability of an adult using their smartphone on meetings or classes is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

63% use them in meetings or classes.

This means that p = 0.63

7 adult smartphone users are randomly selected

This means that n = 7

Find the probability that exactly 2 of them use their smartphones in meetings or classes.

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{7,2}.(0.63)^{2}.(0.37)^{5} = 0.0578

5.78% probability that exactly 2 of them use their smartphones in meetings or classes.

8 0
3 years ago
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