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3 years ago

find the area of a circle that has a diameter of 11inches approximate as 13.4 round your answer to the hundreth

Mathematics

2 answers:

Soloha48 [4]3 years ago

5 0

radius = 1/2 diameter = 1/2 * 11 = 5.5 ins

area = pi * r^2 = 3.14 * 5.5^2 = 94.99 in^2 to nearest hundredth

Vinil7 [7]3 years ago

3 0

To find the area of a circle you do pi (3.14) multiplied by the radius squared.

The radius is half of the diameter: 11 / 2 = 5.5in

The radius squared is 5.5^2 = 30.25

Then take the squared radius and multiply that by pi 30.25 * 3.14 = 94.985

So the area of the circle is about 94. 99 in.

Hope this helped! Mark as Brainliest please! :)))

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fomenos

Answer:

The correct option is A.

Step-by-step explanation:

It is given that the QRST is a parallelogram and the diagonals QS and RT are congruent.

According to the property of parallelogram if the length of diagonals are same, then the parallelogram is rectangle. We can also prove it.

Let QRST be an parallelogram and QS=RT.

In triangles QRT and RQS.

$RT=QS$ (Diagonals)

$QR=QR$ (Common side)

$QT=RS$ (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QRT and triangle RQS are congruent.

By CPCT,

$\angle R=\angle Q$

Since the sum of two consecutive angles of a parallelogram is 180 degree.

$\angle R+\angle Q=180$

$2\angle R=180$

$\angle R=90$

Therefore the measure of angle R and angle Q are 90 degree.

Similarly in triangle QST and RTS,

$RT=QS$ (Diagonals)

$ST=ST$ (Common side)

$QT=RS$ (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QST and RTS are congruent.

By CPCT,

$\angle S=\angle T$

Since the sum of two consecutive angles of a parallelogram is 180 degree.

Therefore the measure of angle S and angle T are 90 degree.

Since the measure of all interior angles of QRST are 90 degree, therefore the parallelogram QRST is a rectangle.

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Answer:

Step-by-step explanation:

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natima [27]

Answer:

y-coordinate = 0

Step-by-step explanation:

Consider the below diagram attached with this question.

Section formula:

If a point divides a line segment in m:n whose end points are $(x_1,y_1)$ and $(x_2,y_2)$ , then the coordinates of that point are

$(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})$

From the below graph it is clear that the coordinates of end points are J(1,-10) and K(7,2). A point divides the line JK is 5:1.

Using section formula, the coordinates of that point are

$(\frac{(5)(7)+(1)(1)}{5+1},\frac{(5)(2)+(1)(-10)}{5+1})$

$(\frac{35+1}{6},\frac{10-10}{6})$

$(\frac{36}{6},\frac{0}{6})$

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Answer:

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Step-by-step explanation:

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