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dsp73
3 years ago
15

It took Todd 11 hours to travel over pack ice from one town in the Arctic to another town 330 miles away. During the return jour

ney, it took him 15 hours. Assume the pack ice was drifting at a constant rate, and that Todd’s snowmobile was traveling at a constant speed relative to the pack ice. What was the speed of Todd's snowmobile?
Mathematics
1 answer:
KiRa [710]3 years ago
7 0

Answer:

20 mph

Step-by-step explanation:

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If all direct materials are added at the end of the production process, and the units have made it 50% of the way through the pr
ella [17]

Answer:

Answer:option B  100%

Step-by-step explanation:

Since direct materials are added into production process at the end,so it will be more likely to be 100% completed.

8 0
3 years ago
#FleePointsForFlee<br> as you see, #FleePointsForFlee 2
viktelen [127]

tysm luv this #FleePointsForFlee thing!!!!! :))))

4 0
2 years ago
Plz help me with these two problems I’m having such trouble
igomit [66]
For No. 13 you need to calculate the distance each girl travels and compare to see whose distance is greater. The formula for distance is rate x time or d=rt. The rate is just how fast they consistently go.

Mia
d = r x t
d = 14 x 3/2
d = 21 miles

Chloe
d = r x t
d = 35 x 3/4 (btw 3/4 is just 45/60 simplified)
d = 105/4 = 26 1/4 miles

Final Answer: Chloe traveled further

For No. 14 we will recalculate Mia's distance but replace 1/5 hours with 2 hours because it says she will bike 30 minutes after Chloe had stopped. Afterwards we will compare Mia's new distance with Chloe's old distance.

Mia
d = r x t
d = 14 x 2
d = 28 miles

Final Answer: Yes Mia would be able to catch up to Chloe, and even surpass her in 30 minutes if Chloe stopped.

3 0
3 years ago
Need answers for 70-75
adoni [48]

Answer:

70. 0

71. -54

72. 12

73. 86

74. 59

Step-by-step explanation:

To evaluate an expression, substitute specific values for the variables and simplify using Order of Operations.

70. c-3d becomes

(1)-3(\frac{1}{3}) = 1-(\frac{3}{3}) = 1-1 = 0

71. x+x^3-4x^4 becomes

2+2^3-4(2)^4 = 2+8-4(16) = 2+8-64=10-64=-54

72. 5a+3a^2 becomes

5(-3)+3(-3)^2 = -15 +3(9) = -15 + 27 = 12

73. F=\frac{9}{5}C+32 becomes

F=\frac{9}{5}(30)+32=\frac{270}{5}+32 = 54+32 = 86

74.  F=\frac{9}{5}C+32 becomes

F=\frac{9}{5}(15)+32=\frac{135}{5}+32 = 27+32 = 59

8 0
3 years ago
10 Pts <br> Multiplying fractions:<br><br> 5     1 <br> — x — = <br> 6     2
Flauer [41]

Multiply the numerators together. Multiply the denominators together. Then reduce if necessary.

\dfrac{first~numerator}{first~denominator} \times \dfrac{second~numerator}{second~denominator} = \dfrac{(first~numerator)\times(second~numerator)}{(first~denominator)\times(second~denominator)}

\dfrac{a}{b} \times \dfrac{c}{d} = \dfrac{a \times c}{b \times d}

\dfrac{5}{6} \times \dfrac{1}{2} = \dfrac{5 \times 1}{6 \times 2} = \dfrac{5}{12}

6 0
4 years ago
Read 2 more answers
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