<h3>Answer: Choice C. </h3><h3>Division[ (4x^3+2x^2+3x+5)^2, x^2+3x+1]</h3>
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Explanation:
It honestly depends on the CAS program, but for GeoGebra for instance, the general format would be Division[P, Q]
Where,
- P = numerator = (4x^3+2x^2+3x+5)^2
- Q = denominator = x^2+3x+1
As another example, let's say we want to divide x^2+5x+6 all over x^3+7 as one big fraction
We would type in Division[x^2+5x+6, x^3+7]
Answer:
Congrats!
Step-by-step explanation:
Given that 
, and 
, this first step can be to make the equations equivalent to one another. As you can see, each equation is equal to a constant, e. Therefore, we can conclude that the equations can be equal to one another as well ( transitivity ).
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Nice and simple question we have here! The step that can be used to find the solution should be 
.
Y= -5x -4 because you would do slope intercept form and sub the y and x in for -4 and 0
