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2 years ago

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A number is less than 20 units away from 7 on the number line. What numbers are within these parameters? Choose the inequality t

hat represents the situation.

2 answers:

hichkok12 [17]2 years ago

6 0

Answer:

1. B

2. D

3. D

Step-by-step

took it on edge

Alex787 [66]2 years ago

5 0

Answer:

For the pull out menu it was B

Step-by-step explanation:

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At the carnival, 3 rides on the MoonCoaster cost $21. How much<br> do 5 rides cost?

Bogdan [553]

Answer:

$35 dollars

Step-by-step explanation:

So we know that 3 rides costs $21. If you then take 21/3 you get 7, you're then going to take 7x5 and you will get 35. Therefore 5 rides on the MoonCoaster cost $35. Hope this helps!

4 0

2 years ago

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The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). On a coordinate plane, line A B has points (4, 1) and (n

GarryVolchara [31]

Answer:

$(-1,1),(4,-2)$

Step-by-step explanation:

Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

To find: coordinates of vertex of the right angle

Solution:

Let C be point $(x,y)$

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AC=\sqrt{(x-4)^2+(y-1)^2}\\BC=\sqrt{(x+1)^2+(y+2)^2}\\AB=\sqrt{(4+1)^2+(1+2)^2}=\sqrt{25+9}=\sqrt{34}$

ΔABC is a right angled triangle, suing Pythagoras theorem (square of hypotenuse is equal to sum of squares of base and perpendicular)

$34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]$

Put $(x,y)=(-1,1)$

$34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34$

which is true. So, $(-1,1)$ can be a vertex

Put $(x,y)=(4,-2)$

$34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34$

which is true. So, $(4,-2)$ can be a vertex

Put $(x,y)=(1,1)$

$34=\left [ (1-4)^2+(1-1)^2 \right ]+\left [ (1+1)^2+(1+2)^2 \right ]\\34=9+4+9\\34=22$

which is not true. So, $(1,1)$ cannot be a vertex

Put $(x,y)=(2,-2)$

$34=\left [ (2-4)^2+(-2-1)^2 \right ]+\left [ (2+1)^2+(-2+2)^2 \right ]\\34=4+9+9\\34=22$

which is not true. So, $(2,-2)$ cannot be a vertex

Put $(x,y)=(4,-1)$

$34=\left [ (4-4)^2+(-1-1)^2 \right ]+\left [ (4+1)^2+(-1+2)^2 \right ]\\34=4+25+1\\34=30$

which is not true. So, $(4,-1)$ cannot be a vertex

Put $(x,y)=(-1,4)$

$34=\left [ (-1-4)^2+(4-1)^2 \right ]+\left [ (-1+1)^2+(4+2)^2 \right ]\\34=25+9+36\\34=70$

which is not true. So, $(-1,4)$ cannot be a vertex

So, possible points for the vertex are $(-1,1),(4,-2)$

7 0

2 years ago

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Look at the triangle.

Gekata [30.6K]

Answer:

Ok, Sir, The answer is D.

Step-by-step explanation:

From the list of possible answers, the sides are 5 and 12 and the hypotenuse is 13, so sin(x) is either 5/13 or 12/13 depending on which of the two legs is opposite to angle x.

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2 years ago

What's<br> 1831 divided be 51?

Shtirlitz [24]

your answer to that division problem is 35.9

7 0

3 years ago

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Is 5,577 + 617,667 positive or negative?

raketka [301]

I’m pretty sure that’s a positive :0

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2 years ago

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