Question

How many triangles are there that satisfy the conditions a =13, b =9, A = 62°?

Answer 1

Answer:

Step-by-step explanation:

Alright, lets get started.

Using sin Law,

$\frac{sinA}{a}=\frac{sinB}{b}$

Plugging the value of a, b and angle A

$\frac{sin62}{13}=\frac{sinB}{9}$

$sinB=\frac{9*sin62}{13}$

$sinB=\frac{9*0.8829}{13}$

$sinB=0.61127$

taking sin inverse on both sides

$B=sin^{-1}(0.61127) =37.68$

The may be another value of B that will called B' = $180-37.68=142.32$

We will not consider this B' value because the um of angle B' and A will exceeds 180 degree ($142.32+62=204.32$)

Thats why only one triangle is possible.   :   Answer

Hope it will help :)