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3 years ago

This question is really hard can someone please help out? Thank you so much !!!

Mathematics

1 answer:

atroni [7]3 years ago

3 0

Answer: Option 4: -2sin(x + pi/2) - 1

Step-by-step explanation:

When this equation is graphed, the y-intercept is -3 which is what the image shows. None of the others have a y-intercept at -3.

Hope this helps!

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PLEASE HELP!! BRAINLIEST ANSWER AND FASTEST ANSWER GETS TON OF FREE POINTS...MATH WHIZZES, HELP ME OUT. FORGOT HOW TO DO THIS.

Julli [10]

Inscribed angles equal half of their arc length. So <D+ <B = 180
substitute: x+24+x+10 = 180
solve: 2x + 34 = 180
2x= 146
x= 73
NOw find the measure of angle A:
<a = x + 15
<a = 73 + 15
<a = 88
Now to find <C
<C = 180- 88
<C = 92
Hope this helps!

5 0

3 years ago

Please someone help!<br> Find ∛-27

Westkost [7]

Answer:

∛-27 or -3

Step-by-step explanation:

I don't think you can do anything further to this problem unless we have to solve for something.

If it is 3 square root of the whole thing, then the answer is -3 because

-3 x -3 x -3 = -27

-3 x -3 = negative x negative = positive = 9

9 x -3 = positive x negative = negative = -27

Hope this helps!

6 0

3 years ago

Read 2 more answers

Find the surface area of this triangular prism. Be sure to include the correct unit in your answer.

BartSMP [9]

Answer:

905 is the perimeter

and the triangular prism is 46

Step-by-step explanation:

mark me BRAINLIEST

4 0

3 years ago

Evaluate the iterated integral. $$ \int\limits_0^{2\pi}\int\limits_0^y\int\limits_0^x {\color{red}9} \cos(x+y+z)\,dz\,dx\,dy $$

KengaRu [80]

$\displaystyle\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\int_{z=0}^{z=x}\cos(x+y+z)\,\mathrm dz\,\mathrm dx\,\mathrm dy=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(x+y+z)\bigg|_{z=0}^{z=x}\,\mathrm dx\,\mathrm dy$
$\displaystyle=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(2x+y)-\sin(x+y)\,\mathrm dx\,\mathrm dy$
$\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left(\cos(2x+y)-2\cos(x+y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dx\,\mathrm dy$
$\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left((\cos3y-2\cos2y)-(\cos y-2\cos y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dy$
$\displaystyle=-\frac12\int_{y=0}^{y=2\pi}(\cos3y-2\cos2y+\cos y)\,\mathrm dy$
$\displaystyle=-\frac12\left(\frac13\sin3y-\sin2y+\sin y\right)\bigg|_{y=0}^{y=2\pi}$
$=0$

4 0

3 years ago

Which of the following represents a relation that is not a function?

Inessa05 [86]

Answer:

x -7 -5 -1 1

y 33 31 39 33

Step-by-step explanation:

think so

6 0

2 years ago