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dimulka [17.4K]
2 years ago
10

Consider the following 8 numbers, where one labelled x is unknown. 4, 32, 6, x , 10, 3, 35, 37 Given that the range of the numbe

rs is 64, work out 2 values of x
Mathematics
2 answers:
Natali [406]2 years ago
8 0

Answer:

\boxed{x=-27, \: x=67}

Step-by-step explanation:

There can be two values of x.

The range is largest no. - smallest no.

Range = 64

Let x be the smallest no.

largest no. from the list is 37

37 - x = 64

-x = 64 - 37

x = -27

Let x be the largest no.

smallest no. from the list is 3

x - 3 = 64

x = 64 + 3

x = 67

V125BC [204]2 years ago
8 0

Answer:

<h3>x = -27 , x = 67</h3>

Step-by-step explanation:

Given data : 4 , 32 , 6 , x , 10 , 3 , 35 , 37

Range = 64

Range is the difference between highest term and lowest term.

Here, highest term is 37 and lowest term is 3. Hence, x can be highest or lowest term.

37 - x = 64

Move constant to R.H.S and change its sign

-x = 64 - 37

Calculate the difference

-x = 27

Change the signs on both sides of the equation

x = -27

Again,

x - 3 = 64

Move constant to R.H.S and change its sign

x = 64 + 3

Calculate the sum

x = 67

So, possible values of X are:

-27 and 67

Hope this helps...

Best regards!!

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Answer:

Part A)

A reasonable domain to plot the growth function is:

0\leq d \leq 12

Part B)

The <em>y-</em>intercept represents that when the biologist started her study, the radius of the algae was five millimeters.

Part C)

The average rate of change from <em>d</em> = 4 to <em>d</em> = 11 was about 0.11. This means that from the 4th day to the 11th, the radius of the algae grew, on average, at a rate of 0.11 mm per day.

Step-by-step explanation:

The radius of the algae f(d) in millimeters after <em>d</em> days is given by the function:

f(d)=5(1.02)^d

Part A)

We know that the radius of the algae was approximately 6.34 mm when the biologist concluded her study. To find the reasonable domain, we can substitute 6.34 for f(d) and solve for <em>d</em>. Therefore:

6.34=5(1.02)^d

Divide both sides by five:

(1.02)^d=1.268

Take the log of both sides with base 1.02:

\displaystyle d=\log_{1.02}1.268

Using the Change of Base Property, evaluate for <em>d: </em>

<em />\displaystyle d=\frac{\log 1.268}{\log 1.02}=11.9903...\approx 12<em />

So, the biologist concluded her study after 12 days.

Therefore, a reasonable domain to plot the growth function is:

0\leq d\leq 12

Part 2)

The <em>y-</em>intercept of the function is when <em>d</em> = 0. Find the <em>y-</em>intercept:

f(0)=5(1.02)^{(0)}=5(1)=5

Since <em>d</em> represent the amount of days after the study had begun, the <em>y-</em>intercept represents the radius of the algae on the initial day.

So, when the biologist started her study, the radius of the algae was five millimeters.

Part 3)

To find the average rate of change for a nonlinear function, we find the slope between the two endpoints on the interval.

We want to find the average rate of change of f(d) from <em>d</em> = 4 to <em>d</em> = 11.

Find the endpoints:

f(4)=5.4121...\text{ and } f(11)=6.2168...

And find the slope between them:

\displaystyle m=\frac{f(11)-f(4)}{11-4}=0.1149...\approx 0.11

Since f(d) measures millimeters and <em>d</em> measures days, this tells us that, on average, the radius of the algae grew by about 0.11 mm per day from the 4th day to the 11th day.

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timama [110]

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Step-by-step explanation:

360° - 210° = 150° .......

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