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dimulka [17.4K]
3 years ago
10

Consider the following 8 numbers, where one labelled x is unknown. 4, 32, 6, x , 10, 3, 35, 37 Given that the range of the numbe

rs is 64, work out 2 values of x
Mathematics
2 answers:
Natali [406]3 years ago
8 0

Answer:

\boxed{x=-27, \: x=67}

Step-by-step explanation:

There can be two values of x.

The range is largest no. - smallest no.

Range = 64

Let x be the smallest no.

largest no. from the list is 37

37 - x = 64

-x = 64 - 37

x = -27

Let x be the largest no.

smallest no. from the list is 3

x - 3 = 64

x = 64 + 3

x = 67

V125BC [204]3 years ago
8 0

Answer:

<h3>x = -27 , x = 67</h3>

Step-by-step explanation:

Given data : 4 , 32 , 6 , x , 10 , 3 , 35 , 37

Range = 64

Range is the difference between highest term and lowest term.

Here, highest term is 37 and lowest term is 3. Hence, x can be highest or lowest term.

37 - x = 64

Move constant to R.H.S and change its sign

-x = 64 - 37

Calculate the difference

-x = 27

Change the signs on both sides of the equation

x = -27

Again,

x - 3 = 64

Move constant to R.H.S and change its sign

x = 64 + 3

Calculate the sum

x = 67

So, possible values of X are:

-27 and 67

Hope this helps...

Best regards!!

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Answer:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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If you have a cube measuring 1 unit on each side, how many of those cubes would fit into a space 2 units by 3 units by 4 units
alisha [4.7K]

Given:

Measure of a cube = 1 unit on each side.

Dimensions of a space 2 units by 3 units by 4 units.

To find:

Number of cubes that can be fit into the given space.

Solution:

The volume of cube is:

V_1=a^3

Where, a is the side length of cube.

V_1=(1)^3

V_1=1

So, the volume of the cube is 1 cubic units.

The volume of the cuboid is:

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Where, l is length, w is width and h is height.

Putting l=2,b=3,h=4, we get

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V_2=24

So, the volume of the space is 24 cubic units.

We need to divide the volume of the space by the volume of the cube to find the number of cubes that can be fit into the given space.

n=\dfrac{V_2}{V_1}

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