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dsp73
3 years ago
13

A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is 5.0 × 10

-4 seconds, what is the value of impulse?
Physics
2 answers:
dimaraw [331]3 years ago
7 0
This question could be solved with this formula:
F . ΔT
From which F= The amount of force applied
and ΔT = the impact time ins seconds

So, the Value of impulse would be:
520 N x 5. x 10^-4 seconds

= 0.052 N x 5

= 0.26 Newton Seconds
Dmitry_Shevchenko [17]3 years ago
5 0

Answer:

Explanation:

0.26n/s CORRECT ON PLATO

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3 years ago
Two particles execute simple harmonic motion of the same amplitude and frequency along close parallel lines. They pass each othe
deff fn [24]

Answer:

\theta_2 - \theta_1 = 156.93 degree

Explanation:

As we know that the displacement of the particle from the mean position is 1/5 times of its amplitude

so we have

y = A sin\omega t

y = \frac{A}{5}

so now we have

\frac{A}{5} = A sin\omega t

now we have

\theta_1 = 11.53 degree

so the phase other particle in opposite direction is given as

\theta_2 = 180 - 11.53 = 168.46 degree

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\theta_2 - \theta_1 = 168.46 - 11.53

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7 0
3 years ago
The stoplights on a street are designed to keep traffic moving at 26 mi/h. the average length of a street block between traffic ligh
bonufazy [111]

We use the formula,

v = \frac{d}{t}.

Here, v is velocity and its value given 26 mi/h ( in m/s,  \frac{26 \times 1.609 \times 10^{3} m}{60 \times 60 s} =11.62 \ m/s ) and d is distance and its value is given 80 m.

Substituting these values in above formula we get,

t = \frac{80 m}{11.62m/s } = 6.88 \ s

Thus, the time delay between green lights on successive blocks to keep the traffic moving continuously is 6.88 s


3 0
3 years ago
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