What type of stimulus do we tend to be particularly aware of ?

A stone is thrown vertically upward with a speed of 24.0 ms. (a) How fast is it moving when it reaches a height of 13.0 m? (b) H

valina [46]

Answer:

Question A:17.92 m/s

Question B:0.6 seconds

Explanation:

Question A:

Initial velocity(u)=24m/s

Height(h)=13m

acceleration due to gravity(g)=9.8m/s^2

Final velocity=v

v^2=u^2-2xgxh

v^2=24^2-2x9.8x13

v^2=24x24-2x9.8x13

v^2=576-254.8

v^2=321.2

Take them square root of both sides

v=√(321.2)

v=17.92m/s

Question B:

velocity(v)=17.92m/s

Acceleration due to gravity(g)=9.8m/s^2

Initial velocity(u)=24m/s

Time=t

v=u-gxt

17.92=24-9.8xt

Collect like terms

9.8t=24-17.92

9.8t=6.08

Divide both sides by 9.8

9.8t/9.8=6.08/9.8

t=0.6 approximately

5 0

3 years ago

Io and Europa are two of Jupiter's many moons. The mean distance of Europa from Jupiter is about twice as far as that for Io and

Anastaziya [24]

The universal gravitation law and Newton's second law allow us to find that the answer for the relation of the rotation periods of the satellites is:

$\frac{T_{Eu}}{T_{Io}}$ = 2.83

The universal gravitation law states that the force between two bodies is proportional to their masses and inversely proportional to their distance squared

$F = G \frac{Mm}{r^2}$

Where G is the universal gravitational constant (G = 6.67 10⁻¹¹ $\frac{N m^2 }{kg^2}$ ), F the force, m and m the masses of the bodies and r the distance between them

Newton's second law states that force is proportional to the mass and acceleration of bodies

F = m a

Where F is the force, m the mass and the acceleration

In this case the body is the satellites of Jupiter and the planet,

$G \frac{Mm}{r^2} = m a$

Suppose the motion of the satellites is circular, then the acceleration is centripetal

a = $\frac{v^2}{r}$ r

Where v is the speed of the satellite and r the distance to the center of the planet

we substitute

$G \frac{Mm}{r^2} = m \frac{v^2}{r} \\G \frac{M}{r} = v^2$

Since the speed is constant, we can use the uniform motion ratio

v = $\frac{\Delta x}{t}$

In the case of a complete orbit, the time is called the period.

The distance traveled is the length of the orbit circle

Δx = 2π r

We substitute

$G \frac{M}{r} = (\frac{2 \pi r}{T} )^2 \\T^2 = (\frac{4 \pi ^2}{GM}) \ r^3$

Let's write this expression for each satellite

Io satellite

Let's call the distance from Jupiter is

r = $r_{Io}$

$T_{Io}^2 = (\frac{4 \pi ^2}{GM} ) \ r_{Io}^3$ TIo² = (4pi² / GM) rIo³

Europe satellite

Distance from Jupiter is

$r_{Eu} = 2 \ r_{Io}$

We calculate

$T_{Eu} = ( \frac{4\pi ^2 }{GM} (2 \ r_{Io})^3\\T_{Eu} = ( \frac{4 \pi ^2 }{GM}) r_{Io} \ 8$

$T_{Eu}^2 = 8 T_{Io}^2$

$\frac{ T_{Eu}}{T_{Io}} = \sqrt{8} = 2.83$

In conclusion, using the universal gravitation law and Newton's second law, we find that the answer for the relationship of the relation periods of the satellites is:

$\frac{T_{Eu}}{T_{Io}} = 2.83$

Learn more about universal gravitation law and Newton's second law here:

brainly.com/question/10693965

6 0

3 years ago

_____ are marketing intermediaries that sell directly to final consumers.

Sidana [21]

Retailers are marketing intermediaries that sell directly to final consumers.

Wholesalers are those who sell to the retailers.
Distributors are those who buys non competing product lines and sells them to wholesalers and retailers.

7 0

3 years ago

,how do charged objects react???quiet urgent

son4ous [18]

Any charged object can exert the force upon other objects ... i think tell me if im right

8 0

3 years ago

Read 2 more answers

A. 2kg B. 6kg C. 8kg D. 14kg

Sati [7]

Answer:

A

Explanation:

We know the force is (16N-12), which is 4N, and we know the acceleration is 2 m/s^2. Meaning, we can solve the formula m = F / a (mass equals force divided by acceleration), and we get 2kg.

7 0

3 years ago