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Verdich [7]
3 years ago
8

What is Graph the line y=-8

Mathematics
1 answer:
aksik [14]3 years ago
3 0
The line should be parallel to X

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On the coordinate plane below, Point P, is located at (2,-3) and point Q is located at (-4,4). Find the distance between points,
marishachu [46]

Answer:

approximately 9.2195

Step-by-step explanation:

We can use Pythagorean theorem

one leg is 7 and the other leg is 6

square them

49 and 36

add

85

square root

approximately 9.2195

4 0
2 years ago
Juanita is planting a flower garden. She wants to plant 24 tulips, and twice as many daffodils as tulips. A tulip plant costs $3
slavikrds [6]

Answer:

The total cost is \$168

Step-by-step explanation:

Let

x-----> the number of tulips

y-----> the number of daffodils

C-----> the total cost

we know that

x=24\ tulips

y=2x

substitute the value of x

y=2(24)=48\ daffodils

Find the total cost

C=3x+2y

substitute

C=3(24)+2(48)=\$168

5 0
2 years ago
Please help me!
Tamiku [17]
Check the picture below.

notice the sides, now, on the second triangle, side 6 slants a bit more to fit in 13, on the third triangle, side 6 slants even further to fit 13 in, now, if 6 were to slant completely, it'll make a flat-line with side 5, and there will be a triangle no more.

but even if side 6 would stretch to a flat-line, 5+6 is just 11, whilst side 13 is longer than that, so no dice.

4 0
3 years ago
The weights of 1250 pumpkins are normally distributed with mean of 28 pounds and a standard deviation of 6 pounds. About how man
Mekhanik [1.2K]
Kropot72
kropot72 3 years ago
This can be solved by using a standard normal distribution table. The z-score for 34 pounds is 1, the reason being that 34 is one standard deviation above the mean of 28 pounds.
Can use the table to find the cumulative probability for z = 1.00 and post the result? If you do this we can do the next simple steps.
5 0
2 years ago
At 8:00 a.m. the temperature outside in Juneau, Alaska was -16.5 . By noon the temperature had increased by 15.25 . What is the
adelina 88 [10]

It would be -1.25 degrees at noon.

3 0
3 years ago
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