From the function y=x^2-4x+7
to complete the square we proceed as follows:
The vertex form is given by:
y=(x-h)^2+k
where (h,k) is the vertex:
thus from the function we shall have:
y=x^2-4x+7
c=(b/2a)²
c=(4/2)²=4
thus adding an subtracting 4 in the expression:
y=x^2-4x+4-4+7
y=(x-2)^2+3
thus the vertex will be:
(2,3)
The answer is:
<span>D. Minimum at (2, 3)</span>
Furthest from 0, so I am going to take the absolute value of these numbers. The absolute value will tell us how far away from 0 these numbers are.
|-1/2| = |- 0.5| = 0.5
|8/9| = |0.88| = 0.88
|0.2| = 0.2
so the number furthest from 0 is 8/9
16 over 3 is the answer u write the numerator above the denominator 6 over 1 minus 2 over 3 6 times 3 over 1 x3 minus 2 over 3 u get 18 minus 2 over 3 and subtract 18 and 2 u get 16 over 3
Answer:
, 
, and 
Or
angle PQR, angle SQR and angle PQS
Step-by-step explanation:
The three different angles in the diagram are angle PQR, angle SQR and angle PQS.
Another way of writing this is using an angle sign before the alphabets follows. Thus:
, , and
Answer:
Step-by-step explanation:
(x - 2)(x² + 7x + 4) = x(x² + 7x + 4) - 2*(x² + 7x + 4)
= x*x² + x*7x + 4*x - 2*x² -2* 7x -2* 4
= x³ + 7x² + 4x - 2x² -14x -8
= x³ + <u>7x² - 2x²</u> <u>+ 4x - 14x</u> - 8
= x³ + 5x² - 10x - 8
