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RSB [31]
3 years ago
12

What committee decides which bills move to the House floor for debate and sets the terms for the debate?

Physics
1 answer:
spayn [35]3 years ago
6 0
 i think the answer is B-House Rules Comittee
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Please Help Fast!!!
S_A_V [24]
Aluminum has an atomic number of 13,  so it has 13 protons. In its natural state, it does not have a charge,  so it has an equal amount of electrons, 13. The atomic mass of aluminum is approximately 27. Since protons and neutrons make up that mass, and each of the particles are around 1 atomic mass unit, if there are 13 protons, then there are 27-13 neutrons, or 14 neutrons. So the first answer choice is correct.
6 0
3 years ago
Read 2 more answers
A package of chips weighs 45 grams. How much is that in kilograms?
nirvana33 [79]
45 grams is 0.045 kilograms
5 0
3 years ago
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PLEASE HELP I NEED THIS DONE TODAY
ratelena [41]
Drinking more water or other fluids
3 0
3 years ago
Car A and Car B approach each other
vagabundo [1.1K]

The original frequency of horn of Car A is 1071 Hz.

Explanation:

Doppler effect describes the change in the frequency of sound waves with respect to the observer. As the sound waves emitted from a source need to travel the air medium to reach observer, it will undergo loss in energy. So there will be change in its frequency compared to original frequency. Depending upon the direction of travel of source and observer the shifting of frequency will vary.

f'=\frac{v-v_{o} }{v-v_{s} } f

Here vo is the observer velocity and vs is the velocity of the source. So Vo = 15 m/s as car B is the observer and Vs = 35 m/s as car A is the source. And f is the frequency of sound wave at source that is car A.

Similarly, the doppler shift in frequency is the frequency of sound heard by car B which is f' = 1140 Hz. And v is the speed of sound that is v = 343 m/s

1140 = \frac{343-15}{343-35}*f= 1.0649 *f

f = 1140/1.0649= 1071 Hz.

Thus, the original frequency of horn of Car A is 1071 Hz.

3 0
3 years ago
A mixture of helium and argon gas is expanded from a volume of 29.0L to a volume of 82.0L, while the pressure is held constant a
finlep [7]

Answer:

322 kJ

Explanation:

The work is the energy that a force produces when realizes a displacement. So, for a gas, it occurs when it expands or when it compress.

When the gas expands it realizes work, so the work is positive, when it compress, it's suffering work, so the work is negative.

For a constant pressure, the work can be calcutated by:

W = pxΔV, where W is the work, p is the pressure, and ΔV is the volume variation. To find the work in Joules, the pressure must be in Pascal (1 atm = 101325 Pa), and the volume in m³ (1 L = 0.001 m³), so:

p = 60 atm = 6.08x10⁶ Pa

ΔV = 82.0 - 29.0 = 53 L = 0.053 m³

W = 6.08x10⁶x0.053

W = 322x10³ J

W = 322 kJ

8 0
3 years ago
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