What is the capital of prince edward island

Physics

1 answer:

Anni [7]4 years ago

8 0

Answer:

The capital of Prince Edward Island is Charlottetown.

Explanation:

hope this helps, and if it did, please mark brainliest :)

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To measure the height of a building without a ruler or tape measure, an engineer drops a rock off the top of the building and fi

serg [7]

The relevant equation we can use in this problem is:

h = v0 t + 0.5 g t^2

where h is height, v0 is initial velocity, t is time, g is gravity

Since it was stated that the rock was drop, so it was free fall and v0 = 0, therefore:

h = 0 + 0.5 * 9.81 m/s^2 * (4.9 s)^2

h = 117.77 m

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3 years ago

Help This is Urgent

MaRussiya [10]

I don’t use the metric system, so I used feet and then went back.

25 meters is about 82 feet.
So around 82 feet per minute (kinda slow LOL)

82 (feet per minute) x 90 (minutes) = 7380 feet (in 90 minutes)

7380 feet is equal to 2249.424 meters.

(I hope that helped)

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3 years ago

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To measure the potential drop across a resistor, a voltmeter is connected in ____ with the resistor.

slava [35]

A voltmeter is connected in PARALLEL with the resistor.

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3 years ago

A supply plane needs to drop a package of food to scientists working on a glacier in greenland. the plane flies 100 m above the

pishuonlain [190]

The package should be dropped 678 m short of the target.

A package dropped from a plane which is moving at a speed v, has a horizontal velocity equal to the horizontal velocity of the plane. It has a parabolic trajectory, traversing a horizontal range x while it falls through a vertical height y.

The package has no initial vertical velocity, and it falls through a height y under the action of the acceleration due to gravity g.

Use the equation,

$y=\frac{1}{2} gt^2$

Write an expression for t, the time taken for the package to fall through y.

$t^2=\frac{2y}{g}$

Substitute 100 m for y and 9.81m/s² for g.

$t^2=\frac{2y}{g}\\ =\frac{2(100m)}{9.81m/s^2} \\ =20.39s^2\\ t=4.52s$

In the time t the package travels a horizontal distance x. The horizontal velocity of the package remains constant, since no force acts along the horizontal direction.

Therefore, the horizontal distance traveled by the package is given by,

$x=vt\\ =(150m/s)(4.52s)\\ =678m$