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sashaice [31]
3 years ago
14

Can someone please help me quick :(

Physics
1 answer:
nekit [7.7K]3 years ago
3 0

Answer:

PE = 0.968  J

Explanation:

the formula for potential elastic energy is

PE = kx^2/2

k = spring constant 6.4 N/m

x = displacement = 75 - 20 = 55 cm = 0.55m

plug these values into the equation

PE = 6.4(0.55)^2 / 2

PE = 0.968  J

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A bike race against the clock takes place on a straight road. Yan drives at 37 km / h and he starts the course 30s before Christ
joja [24]

Given data:

Yan speed;

u_1=37\text{ km/h}

Christopher speed;

u_2=38.9\text{ km/h}

Christophe starts 30 s later than Yan. Therefore, Christophe takes 30 s less than Yan to reach the same distance.

Part (A)

The distance is given as,

d=ut

Let both Yan and Christophe meet at d distance from the start position. Therefore,

u_1t=u_2(t-30)

Substituting all known values,

\begin{gathered} (37\text{ km/h})t=(38.9\text{ km/h})\times(t-30) \\ \frac{(37\text{ km/h})}{(38.9\text{ km/h})}=\frac{(t-30)}{t} \\ 0.95=1-\frac{30}{t} \\ \frac{30}{t}=1-0.95 \\ \frac{30}{t}=0.05 \\ t=\frac{30}{0.05} \\ t=600\text{ s} \end{gathered}

Therefore, 600 s after Yan's departure Christophe will join him.

Part (B)

The distance is given as,

d=u_1t

Substituting all known values,

\begin{gathered} d=(37\text{ km/h})\times(600\text{ s}) \\ =(37\text{ km/h})\times(600\text{ s})\times(\frac{1\text{ hr}}{3600\text{ s}}) \\ \approx6.17\text{ km} \end{gathered}

Therefore, Christophe joins Yan after 6.17 km from the start.

3 0
1 year ago
Could someone summarize these into a paragraph? i'll give brainliest<br> DUE TODAY!!
slamgirl [31]

Answer:

I can't see the picture

Explanation:

Im sorry can you right whats on the picture down in the comments plz.

6 0
3 years ago
Read 2 more answers
Kevin jumps straight up in the air to a height of 1 meter.At the top of his jump, he has potential energy of 1,000 joules.Answer
Llana [10]
Gravitational potential energy can be given by the equation
PE = mgh
where m is the mass,
g is the gravitational constant 9.81 or 10 depending on rounding
and h is the height

well weight is a force equiavlent to
W= m*g

so comparing that to the potential energy equation, divide the potential energy by the height and you will get weight in Newtons


3 0
3 years ago
What is the thinnest film (but not zero) that produces a strong reflection for green light with a wavelength of 500 nm ?
Marizza181 [45]

The thinnest film (but not zero) that produces a strong reflection for green light with a wavelength of 500 nm is <u>200 nm.</u>

<u />

The wavelength of mild, λ = 500 nm

= 500 x 10^-9 m

Refractive index of oil, n1 = 1.25

Refractive index of water, n2 = 1.33

The thickness of the movie, d =?

For a sturdy mirrored image, m = 1

Wavelength, λ= 2 n1 d / m

Thickness, d = λ m / 2 n1

= 500 x 10 -9 * 1 / ( 2 * 1.25 )

= two hundred x 10 -nine m

= 2 hundred nm.

Wavelength is the gap between the same factors (adjacent crests) within the adjacent cycles of a waveform signal propagated in space or alongside a wire. In wireless systems, this duration is usually specified in meters (m), centimeters (cm), or millimeters (mm).

Wavelength may be defined as the space between two successive crests or troughs of a wave. it is measured within the route of the wave.

Wavelength is the distance among two adjacent crests or troughs of a waveform signal propagated in space or along a wire. The wavelength of a wave is usually specified in meters (m), centimeters (cm), or millimeters (mm). The wavelength is inversely related to frequency.

Learn more about Wavelength here brainly.com/question/10750459

#SPJ4

<u />

3 0
2 years ago
A huge (essentially infinite) horizontal nonconducting sheet 10.0 cm thick has charge uniformly spread over both faces. The uppe
TiliK225 [7]

Answer:

E = 6.77 *10^{3} N/C

Explanation:

THE GIVEN sheet can be taken as two horizontal force  with surface charge density is

at one surface is ∈_1 = 95*10^ {-9} C/mm2

at oher surface is ∈_2= -25*10^{-9} C/mm2

the magnitude of electric field due to surface charge is given as\frac{∈}{2∈_O}

So, electric field at P (2 CM below from surface is) = E_1 +E_2

E = \frac{∈_1}{2∈_O} +\frac{∈_2}{2∈_O}

E = \frac{95*10^{-9} +25*10^{-9}}{2*8.85*10^{-12}}

E = 6.77 *10^{3} N/C

8 0
4 years ago
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