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sashaice [31]
3 years ago
14

Can someone please help me quick :(

Physics
1 answer:
nekit [7.7K]3 years ago
3 0

Answer:

PE = 0.968  J

Explanation:

the formula for potential elastic energy is

PE = kx^2/2

k = spring constant 6.4 N/m

x = displacement = 75 - 20 = 55 cm = 0.55m

plug these values into the equation

PE = 6.4(0.55)^2 / 2

PE = 0.968  J

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V_capac (4.3048 s) = (-9V)e ^(-4.3048 s /T)  +  9V

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V_capac (4.3048 s) = 7.1275 V

Q (4.3048 s)  = 89.9mF*(7.1275V) = 0.6407 C

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Q (∞)  = 89.9mF*(9V) = 0.8091 C
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