Answer:
If all these three charges are positive with a magnitude of
each, the electric potential at the midpoint of segment
would be approximately
.
Explanation:
Convert the unit of the length of each side of this triangle to meters:
.
Distance between the midpoint of
and each of the three charges:
Let
denote Coulomb's constant (
.)
Electric potential due to the charge at
:
.
Electric potential due to the charge at
:
.
Electric potential due to the charge at
:
.
While forces are vectors, electric potentials are scalars. When more than one electric fields are superposed over one another, the resultant electric potential at some point would be the scalar sum of the electric potential at that position due to each of these fields.
Hence, the electric field at the midpoint of
due to all these three charges would be:
.
Mass- Mass is measured in kilograms (kg).
Weight- Weight is measured in Newton’s.
There not enough inform here to answer this question
Answer:
<em>Infrared telescope and camera</em>
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Explanation:
An infrared telescope uses infrared light to detect celestial bodies. The infrared radiation is one of the known forms of electromagnetic radiation. Infrared radiation is given off by a body possessing some form of heat. All bodies above the absolute zero temperature in the universe radiates some form of heat, which can then be detected by an infrared telescope, and infrared radiation can be used to study or look into a system that is void of detectable visible light.
Stars are celestial bodies that are constantly radiating heat. In order to see a clearer picture of the these bodies, <em>Infrared images is better used, since they are able to penetrate the surrounding clouds of dust,</em> and have located many more stellar components than any other types of telescope, especially in dusty regions of star clusters like the Trapezium cluster.
This is the same question as the one previously but with more details, so I will just use my previous answer.
1800 to 1820 is 20 minutes.1830 to 1838 is 8 minutes.1840 to 1905 is 25 minutes.
The total time travelled is 20+8+25 = 53 minutes = 3180 seconds.
The distance between Glasgow and Edinburgh is 28 + 12 + 34 = 74 km = 74000 m.
So, the average speed is 74000m/3180s = 23.27 m/s (4 s.f.)