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vagabundo [1.1K]
3 years ago
5

Things plants make during photosynthesis​

Physics
2 answers:
Anvisha [2.4K]3 years ago
5 0

Answer:

glucose

Explanation:

convert starch to glucose

Nostrana [21]3 years ago
3 0

Answer:

During the process of photosynthesis, cells use carbon dioxide and energy from the Sun to make sugar molecules and oxygen. These sugar molecules are the basis for more complex molecules made by the photosynthetic cell, such as glucose.

I hope it's helpful!

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The process by which a cell captures the energy in sunlight and uses it to make food is called
olga_2 [115]
Photosynthesis- produced by a producer the capture light and convert it into glucose/ carbohydrates or "food" <span />
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3 years ago
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A turntable is designed to acquire an angular velocity of 32.4 rev/s in 0.5 s, starting from rest.
horrorfan [7]
Well, the acceleration is the difference of speeds divided by the time period. \frac{32.4}{0.5}=64.8rev/s^2.
One rev/s is 2\pi rad/s^2, so our final result is 64.8*2\pi=407.15rad/s^2.
3 0
3 years ago
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A watering can is most likely measured in which metric unit
Iteru [2.4K]
A watering can is used to hold a water that we will use to water the plants. The water has both mass and volume. Two watering cans are most often different by the volume they contain. 

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3 0
3 years ago
A vibrating object produces periodic waves with a wavelength of 53 cm and a frequency of 15 Hz. How fast do these waves move awa
DerKrebs [107]

Answer:

v = 7.95 m/s

Explanation:

Given that,

Wavelength of a wave, \lambda=53\ cm=0.53\ m

Frequency of a wave, f = 15 Hz

We need to find the speed of the wave. The speed of a wave is given by :

v=f\lambda\\\\v=15\ Hz\times 0.53\ m\\\\v=7.95\ m/s

So, the wave move with a speed of 7.95 m/s.

5 0
3 years ago
A 3 kg penguin is pushed by his penguin friends who give him an initial speed vo at the top of a 30 m hill. The penguin is hopin
Strike441 [17]

Answer:

This question can be answered by using conversation of energy.

K_1 + U_1 = K_2 + U_2

\frac{1}{2}mv_{0}^2 + mgh_1 = 0 + mgh_2

\frac{1}{2}(3)v_0^2 + (3)(9.8)(30) = (3)(9.8)(45)\\\frac{1}{2}(3)v_0^2 = 441\\v_0^2 = 294\\v_0 = 17.14 m/s

Explanation:

Note that we take K_2 = 0 because we are looking for the minimum initial speed for the penguin to reach the top of the second hill. Any other speed more than this will already be enough for him.

7 0
3 years ago
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