Answer:
a)Yes will deform plastically
b) Will NOT experience necking
Explanation:
Given:
- Applied Force F = 850 lb
- Diameter of wire D = 0.15 in
- Yield Strength Y=45,000 psi
- Ultimate Tensile strength U = 55,000 psi
Find:
a) Whether there will be plastic deformation
b) Whether there will be necking.
Solution:
Assuming a constant Force F, the stress in the wire will be:
stress = F / Area
Area = pi*D^2 / 4
Area = pi*0.15^2 / 4 = 0.0176715 in^2
stress = 850 / 0.0176715
stress = 48,100.16 psi
Yield Strength < Applied stress > Ultimate Tensile strength
45,000 < 48,100 < 55,000
Hence, stress applied is greater than Yield strength beyond which the wire will deform plasticly but insufficient enough to reach UTS responsible for the necking to initiate. Hence, wire deforms plastically but does not experience necking.
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Hydrogen, helium, and carbon.
Answer:
If the particle is an electron 
If the particle is a proton, 
Explanation:
Initial speed at the origin, 
to +ve x-axis
The particle crosses the x-axis at , x = 1.5 cm = 0.015 m
The particle can either be an electron or a proton:
Mass of an electron, 
Mass of a proton, 
The electric field intensity along the positive y axis 
, can be given by the formula:
If the particle is an electron:
If the particle is a proton:
Answer:
Equilibrium quantity = 5
Equilibrium price = 40
Explanation:
given:
p = -x²-3x+80
p = 7x+5
For the equilibrium quantity the price from both the functions will be equal
thus, we have
-x² - 3x + 80 = 7x+5
⇒ x² +3x + 7x + 5 - 80 = 0
⇒x² + 10x - 75 = 0
now solving for x
x²- 5x + 15x -75 = 0
x(x-5) + 15(x-5) = 0
therefore, the two roots of the equation are
x = 5 and x = -15
since the quantity cannot be in negative
therefore, the equilibrium quantity will be = 5
now the equilibrium price can be found out by substituting the equilibrium quantity in any of the equation
thus,
p = -(5)² -3(5) + 80 = 40
or
p = 7(5) + 5 = 40
