All categories

3 years ago

Please help me with this thanks

Mathematics

1 answer:

Kryger [21]3 years ago

8 0

Step-by-step explanation:

B = area of the base

= 9×4 = 36 square inches

P= perimeter of the base

= 2(9+4)

=2×13= 26 inches

H =distance between the bases

= 16 inches

SA= 2B+PH

= 2(36)+ 26× 16

= 72+416 = 488 square inches

You might be interested in

Write 19/25 as a terminating decimal

mariarad [96]

Terminating decimals firstly are decimals that finish...
To transfer 19/25 to a decimal we have to get it out of 100.
To do this, multiply 19 by 4, and 25 by 4.
This gives you 76/100.
From here you can easily see the decimal is 0.76.

= 0.76

8 0

3 years ago

23 ones times 2 tens

grandymaker [24]

Answer:

460

Step-by-step explanation:

23x20=460

3 0

3 years ago

Read 2 more answers

Find the present value of $10000 if interest is paid at a rate of 8% per year compounded annually for 3 years?

aliya0001 [1]

10,000*0.08*3= <span>$2400.00</span>

5 0

3 years ago

What is the value of x in the equation 4/3/10

Monica [59]

The value of X in the equation is -3

6 0

3 years ago

Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a

Vitek1552 [10]

Answer:

$2ab - 6a + 5b - 15$

Step-by-step explanation:

Given

$2ab - 6a + 5b + \_$

Required

Fill in the gap to produce the product of linear expressions

$2ab - 6a + 5b + \_$

Split to 2

$(2ab - 6a) + (5b + \_)$

Factorize the first bracket

$2a(b - 3) + (5b + \_)$

Represent the _ with X

$2a(b - 3) + (5b + X)$

Factorize the second bracket

$2a(b - 3) + 5(b + \frac{X}{5})$

To result in a linear expression, then the following condition must be satisfied;

$b - 3 = b + \frac{X}{5}$

Subtract b from both sides

$b - b- 3 = b - b+ \frac{X}{5}$

$- 3 = \frac{X}{5}$

Multiply both sides by 5

$- 3 * 5 = \frac{X}{5} * 5$

$X = -15$

Substitute -15 for X in $2a(b - 3) + 5(b + \frac{X}{5})$

$2a(b - 3) + 5(b + \frac{-15}{5})$

$2a(b - 3) + 5(b - \frac{15}{5})$

$2a(b - 3) + 5(b - 3)$

$(2a + 5)(b - 3)$

The two linear expressions are $(2a+ 5)$ and $(b - 3)$

Their product will result in $2ab - 6a + 5b - 15$

<em>Hence, the constant is -15</em>

3 0

3 years ago