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adelina 88 [10]
3 years ago
13

I need help ASAP anyone?

Mathematics
1 answer:
Verdich [7]3 years ago
8 0
<h3>Answer: Choice A</h3>

Explanation:

Each vertical asymptote is due to a division by zero error.

For instance, the vertical asymptote x = 3 is from the factor (x-3) in the denominator. If we plugged x = 3 into (x-3), then it turns into 0 and we cannot have 0 in the denominator.

Similarly, the factor (x+3) leads to x = -3

So overall, we have (x-3)(x+3) in the denominator.

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Order the sides or angles of each triangle from least to greatest.
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SU , UT , ST

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The main cost will be 142.69.


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Probe that:<br><img src="https://tex.z-dn.net/?f=%20%5Csec%20%5Calpha%20%20%5Csqrt%7B1%20-%20%20%5Csin%28%20%7B%7D%5E%7B2%7D%20%
Nataly [62]

Step-by-step explanation:

<h3>\sec \alpha  \sqrt{1 -  \sin ^{2}   \alpha }  = 1</h3>

Prove the LHS

Using trigonometric identities

That's

<h3>\cos ^{2}  \alpha  = 1 -  \sin^{2}  \alpha</h3>

<u>Rewrite the expression</u>

We have

<h3>\sec \alpha  \sqrt{ \cos^{2} \alpha  }</h3>

<h3>\sqrt{ { \cos }^{2}  \alpha }  =  \cos \alpha</h3>

So we have

<h3>\sec  \alpha  \times  \cos \alpha</h3>

Using trigonometric identities

<h3>\sec \alpha  =  \frac{1}{ \cos \alpha }</h3>

<u>Rewrite the expression</u>

That's

<h3>\frac{1}{\cos \alpha }  \times  \cos \alpha</h3>

Reduce the expression with cos a

We have the final answer as

<h2>1</h2>

As proven

Hope this helps you

7 0
3 years ago
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