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CaHeK987 [17]
3 years ago
5

Mass wasting is also commonly triggered by the vibrational waves associated with earthquakes. Explain how earthquakes can disrup

t the frictional and gravitational forces within a slope, causing mass wasting. g
Physics
1 answer:
Law Incorporation [45]3 years ago
5 0

Answer:

The vibrations will put the particles into suspension reducing the frictional forces between them.

Explanation:

The downslope movement of surface material under the direct influence of gravity is called "Mass Wasting." Mass wasting plays a vital role in transferring the products of weathering from their original sites to lower-lying places where the agents of erosion can pick them up for transporting a longer distance.

There are 2 main types of mass wasting;

1. rapid mass movements

2. slow mass movements.

Shearing of soil grains from S-waves rounds jagged corners reducing frictional resistance. Also, Shaking from the seismic waves increases the water content of the material.

Mass movements are part of a continuum of erosional processes between weathering and stream transport. Mass movement causes regolith and rock to move down-slope where sooner or later the loose particles will be picked up by another transporting agent and eventually moved to a site of deposition such as an ocean basin or lake bed.

Mass movement processes are occurring continuously on all slopes; some act very slowly, others occur very suddenly, often with disastrous.

How earthquake cause mass movement

1. Earthquake causes vibrations and this will put the particles into suspension reducing the frictional forces between them.

2. It also cause the shaking from the seismic waves increases the water content of the material.

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Whether we're talking about the gravitational forces of attraction or
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So changing the distance to four times the original distance causes
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8 0
3 years ago
A man attempts to push a 19.8 kg crate across a warehouse floor. He slowly increases the force until the crate starts to move at
VARVARA [1.3K]

Answer:

 μ = 0.18

Explanation:

Let's use Newton's second Law, the coordinate system is horizontal and vertical

Before starting to move the box

Y axis

     N-W = 0

     N = W = mg

X axis

     F -fr = 0

     F = fr

The friction force has the formula

     fr = μ N

     fr =  μ m g

At the limit point just before starting the movement

     F = μ m g

     μ = F / m g

calculate

      μ = 34.8 / (19.8 9.8)

    μ = 0.18

7 0
3 years ago
Read 2 more answers
Which of the following best describes the circuit shown below?
Rudiy27

Answer:

Short circuit

Explanation:

The given figure shows a short circuit. It is defined as the circuit which allows the flow of electric current when there is no resistance. It shows a battery, bulb and connecting wires.

The wire across the bulb is connected from one terminal to another without any resistance in between them.

So, the correct option is (d) " short circuit ".

3 0
3 years ago
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A table exerts a 4.0 Newton force on a book which lies at rest on its top. The force exerted by the book on the table is
SOVA2 [1]
I believe the correct answer from the choices listed above is the third option. <span>The force exerted by the book on the table is equal to the force exerted by the table which is 4.0 N. The book does not move so it must be that the forces are balanced. Hope this answers the question.</span>
4 0
3 years ago
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The net horizontal force on a car is 981 N. The car has a mass of 1550 kg and the force is applied when the car has a speed of 2
viktelen [127]

Answer:

Distance, d = 778.05 m                          

Explanation:

Given that,

Force acting on the car, F = 981 N

Mass of the car, m = 1550 kg

Initial speed of the car, v = 25 mi/h = 11.17 m/s

We need to find the distance covered by car if the force continues to be applied to the car. Firstly, lets find the acceleration of the car:

F=ma\\\\a=\dfrac{F}{m}\\\\a=\dfrac{981}{1550}\\\\a=0.632\ m/s^2

Let d is the distance covered by car. Using second equation of motion as :

d=ut+\dfrac{1}{2}at^2\\\\d=11.17\times 35+\dfrac{1}{2}\times 0.632\times (35)^2\\\\d=778.05\ m

So, the car will cover a distance of 778.05 meters.

5 0
3 years ago
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