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sergij07 [2.7K]
3 years ago
15

If you put 3.27 moles of an ideal

Physics
2 answers:
GenaCL600 [577]3 years ago
5 0

Answer:

1.65 atm

Explanation:

Applying,

PV = nRT....................... Equation 1

Where P = Pressure, V = Volume, n = number of moles, R = malar gas constant, T = Temperature.

Make P the subject of the equation

P = nRT/V..................... Equation 2

From the question,

Given: n = 3.27 moles, V = 50.0 L, T = 35 °C = (273+35) = 308K

Constant: R = 0.082L.atm/K.mol

Substitute these values into equation 2

P = 3.27(0.082)(308)/(50)

P = 1.65 atm

Svetlanka [38]3 years ago
5 0

Answer: 167000

Explanation:

Correct on acellus with three sig figs. Just have to convert atm to Pa

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Mrac [35]

Answer:

X is ammeter and Y is voltmeter

Explanation:

The resistance of a wire is directly proportional to the length of the wire. That is the longer the length of the wire, the higher the resistance and the shorter the length of the wire, the smaller the resistance.

Ammeter is a measuring instrument used to measure the current in a circuit by connecting the meter in series with the circuit.

Ammeter is a measuring instrument used to measure the potential difference between two points by connecting the meter in parallel to the points.

Meter X is an ammeter since it is connected in series and meter Y is a voltmeter because it is connected in parallel.

4 0
3 years ago
A 72-tooth gear is connected to a 12-tooth gear. If the large gear makes one complete turn, how many turns
viktelen [127]
You divide 72 by 12 to get 6.
8 0
3 years ago
The aurora is caused when electrons and protons, moving in the earth’s magnetic field of ≈5.0×10−5T, collide with molecules of t
ollegr [7]

Answer:

8.79*10^6 rad/s

Explanation:

To find the frequency of the circular orbit for an electron you use the following expression, for the radius of the trajectory of an electron, that travels trough a constant magnetic field:

r=\frac{mv}{qB}         (1)

r: radius of the trajectory

m: mass of the electron = 9.1*10^-31 kg

v: speed of the electron = 1.0*10^6 m/s

q: charge of the electron = 1.6*10^-19 C

B: magnitude of the magnetic field = 5.0*10^-5 T

You use the fact that the angular frequency in a circular motion is given by:

\omega=\frac{v}{r}

Then, you solve the equation (1) in order to obtain v/r:

\frac{v}{r}=\omega=\frac{qB}{m}

Finally, you replace the values of the parameters:

\omega=\frac{(1.6*10^{-19}C)(5.0*10^{-5}T)}{9.1*10^{-31}kg}\\\\\omega=8.79*10^6\frac{rad}{s}

hence, the angular frequency is 8.79*10^6 rad/s

The frequency is:

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5 0
3 years ago
Ms. Kasper is in a panic. Her cat, Penny, is stuck in a tree and about to jump out. In order to save her cat, Ms. Kasper needs t
Misha Larkins [42]

Answer:

Speed greater than 4 m/s

Explanation:

Given that Ms. Kasper is in a panic. Her cat, Penny, is stuck in a tree and about to jump out. In order to save her cat, Ms. Kasper needs to run to the tree, 12 meters away. If it takes her cat, 3 seconds to fall, how fast would Ms. Kasper have to run to save her cat?

The distance = 12 m

Time = 3s

Speed = distance/time

Speed = 12/3

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Ms Kasper must run at speed more than 4m/s for her to save the cat.

3 0
3 years ago
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Nataly_w [17]

I think its B B)Warm water rises and cold water moves in to replace it.

7 0
3 years ago
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