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sergij07 [2.7K]
3 years ago
15

If you put 3.27 moles of an ideal

Physics
2 answers:
GenaCL600 [577]3 years ago
5 0

Answer:

1.65 atm

Explanation:

Applying,

PV = nRT....................... Equation 1

Where P = Pressure, V = Volume, n = number of moles, R = malar gas constant, T = Temperature.

Make P the subject of the equation

P = nRT/V..................... Equation 2

From the question,

Given: n = 3.27 moles, V = 50.0 L, T = 35 °C = (273+35) = 308K

Constant: R = 0.082L.atm/K.mol

Substitute these values into equation 2

P = 3.27(0.082)(308)/(50)

P = 1.65 atm

Svetlanka [38]3 years ago
5 0

Answer: 167000

Explanation:

Correct on acellus with three sig figs. Just have to convert atm to Pa

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Suppose the activity of a sample of radioactive material was 100Bq at the start. What would you divide 100Bq by to obtain the ac
myrzilka [38]
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4 0
3 years ago
Does anyone know how to do this?​
SIZIF [17.4K]

Explanation:

By Hooke's Law,

F=kx

The only force acting here is weight, and x is the extension of the string (you need to convert this to mm) so

mg=kx

(0.15)(9.81)=k ((420-300)x10^-3)

Then just solve this equation.

8 0
3 years ago
A hockey player uses her hockey stick to exert a force of 6.81 N on a stationary hockey puck. The hockey puck has a mass of 165
Anna007 [38]

Answer:

41.3 m/s^2 option (e)

Explanation:

force, F = 6.81 N

mass, m = 165 g = 0.165 kg

Let a be the acceleration of the puck.

Use newtons' second law

Force = mass x acceleration

6.81 = 0.165 x a

a = 41.27 m/s^2

a = 41.3 m/s^2

Thus, the acceleration of the puck is 41.3 m/s^2.

5 0
3 years ago
If a ball is launched horizontally at 40 m/s
vaieri [72.5K]

Answer:

40m/s

Explanation:

The horizontal component of velocity remains constant because there are no external forces in that direction

By applying motion equations, V= U+ at

where ,

  • v - final velocity
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  • a-acceleration
  • t - time

v = u +at

As no force act on the ball ( we neglect air resistance here) no acceleration is seen,

So v = u = 40m/s

4 0
3 years ago
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