All categories

3 years ago

If you put 3.27 moles of an ideal

Physics

2 answers:

GenaCL600 [577]3 years ago

5 0

Answer:

1.65 atm

Explanation:

Applying,

PV = nRT....................... Equation 1

Where P = Pressure, V = Volume, n = number of moles, R = malar gas constant, T = Temperature.

Make P the subject of the equation

P = nRT/V..................... Equation 2

From the question,

Given: n = 3.27 moles, V = 50.0 L, T = 35 °C = (273+35) = 308K

Constant: R = 0.082L.atm/K.mol

Substitute these values into equation 2

P = 3.27(0.082)(308)/(50)

P = 1.65 atm

Svetlanka [38]3 years ago

5 0

Answer: 167000

Explanation:

Correct on acellus with three sig figs. Just have to convert atm to Pa

You might be interested in

I NEED HELP THIS QUESTION IS SO HARDDD!!

oksano4ka [1.4K]

Answer:

Explanation:

search it up

8 0

3 years ago

Read 2 more answers

A solenoid coil 10cm long has 40 turns cm-1. The current rises from zero to its maximum value of 5.0000 A and 0000.01s when the

Crank

Answer:

Explanation:

Energy stored in a solenoid per unit volume = B₀² / (2μ₀)

B₀= μ₀ n I₀

n is no of turns per unit length .

Energy stored in a solenoid per unit volume = ( μ₀ n I₀)² / (2μ₀)

=μ₀n²I₀²/2

n = 40 turns / cm = 40 x 100 turns per meter.

I₀ = 5000A .

Putting the values

Energy stored in a solenoid per unit volume

= 4π x 10⁻⁷ x 40 x 10² x 5000² /2

= 1256 J/ m³

Volume of solenoid = cross sectional area x length

= 28 x 10⁻⁴ x .10 = 2.8 x 10⁻⁴ m³

Total energy stored = 1256 J / m³ x 2.8 x 10⁻⁴ m³

= .35 J .

3 0

3 years ago

What is the density of 10 cm^3 volume of water that has a mass of 10g

victus00 [196]

Answer:

Density of water is 1 g/cm³.

Explanation:

Given:

Mass of given volume of water is, $m=10\ g$

Volume of the given amount of water is, $V=10\ cm^3$

We know that, density of a quantity is given as the ratio of its mass to that of its volume.

Here, in order to calculate density of water, we need to divide the mass of water by its volume. Therefore,

$Density=\frac{m}{V}$

Plug in 10 g for 'm', 10 cm³ for 'V and solve for density. This gives,

$Density=\frac{10}{10}\ g/cm^3\\\\Density=1\ g/cm^3$

Therefore, the density of water of mass 10 g and volume 10 cm³ is 1 g/cm³.

5 0

4 years ago

An oscillator makes 360 vibrations in 3 minutes.

IceJOKER [234]

Explanation :

It is given that an oscillator makes 360 oscillations in 3 minutes.

(a) Using unitary method :

No. of vibrations in one minute is, $n=\dfrac{360}{3}=120$

So, no of vibrations in one minute is 120.

(b) Similarly,

3 minutes = 180 seconds

No of vibrations in one second is $\dfrac{360}{180}=2$

So, the no of vibrations in one second is 2.

(c) Time period of the wave is given by :

$T=\dfrac{1}{2\ s^{-1}}$

$T=0.5\ s$

The time period of the wave is 0.5 s

(d) The no of vibation per second is called as its frequency.

$\nu=\dfrac{1}{T}$

$\nu=2\ Hz$

Hence, this is the required solution.

8 0

3 years ago

Read 2 more answers

The energy content of food is conventionally measured in Calories rather than joules. One Calorie in nutrition is equal to 4184

Rama09 [41]

Answer:

Part a)

$P = 186 W$

Part B)

$N = 676 times$

Explanation:

Part a)

Average power is rate of energy consumption

So it is given as

$P = \frac{mgh}{t}$

$P = \frac{100(75.7)(9.81)(0.150)}{59.9}$

$P = 186 W$

Part b)

If the efficiency is given as

$\eta = 20$ %

so we know that 20% of total energy consumed is converted into output work

So total power consumed here will be given as

$P = \frac{186}{0.20}$

$P = 930 W$

Energy consumed by him

$E = power \times time$

$E = 930 \times 59.9$

$E = 55707 J$

now we know that 1 g fat will release 9 Calories energy

So we have

$1 g = 9 \times 4184 J$

$1 g = 37656 J$

so to consume 1000 g of fat we need to release total energy

$E = 37656 \times 10^3 J$

so total number of times

$N = \frac{37656 \times 10^3}{55707}$

$N = 676 times$

5 0

4 years ago