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ziro4ka [17]
3 years ago
9

How many molecules of carbon dioxide are created when 16 molecules of propane react in the following

Chemistry
1 answer:
Grace [21]3 years ago
5 0

Answer:

48 molecules of CO₂

Explanation:

I think you made a mistake in your question.  The formula for propane is C₃H₈, not C₃H₃.  But, I will give you the answer for both cases.

For C₃H₃:

First you have to balance the equation.

4 C₃H₃  +  15 O₂  ⇒  12 CO₂  +  6 H₂O

Next, you need to use the mole ratios between C₃H₃ and CO₂ to find the amount of molecules of CO₂ you will produce with the given amount of C₃H₃.

(16 mol's C₃H₃) × (12 mol's CO₂/4 mol's C₃H₃) = 48 mol's CO₂

You will get 48 molecules of CO₂.

For C₃H₈:

Balance the equation.

C₃H₈  +  5 O₂  ⇒  3 CO₂  +  4 H₂O

Use the mole ratios between C₃H₈ and CO₂.

(16 mol's C₃H₈) × (3 mol's CO₂/1 mol's C₃H₈) = 48 mol's CO₂

You will get 48 molecules of CO₂ for this equation as well.

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What mass of natural gas (CH4) must you burn to emit 264 kJ of heat?
mariarad [96]
The heat released by cpmolete the combustion of organic products with oxygen is called heat of combustion.

Here 1 mol of CH4 realesed 802.3 KJ

To emit 264 kJ you multiply you need (1 mol of CH4/802.3 kJ)* 264 kJ = 0.329 mol of CH4

The molar mass, MM, of CH4 is 12 g/mol + 4*1g/mol = 16 g/mol

The to obtain the mass multiply the number of moles times the molar mass:

mass = n * MM = 0.329mol * 16g/mol = 5.26 grams

Answer: 5.26 grams



7 0
3 years ago
How are compounds with ionic and covalent bonds alike?
PSYCHO15rus [73]

Answer:

B

Explanation:

8 0
3 years ago
Calculate the volume of acetone with the same mass as 15.0 mL of mercury. The density of mercury is 13.59 g/mL. The density of a
lubasha [3.4K]

Answer:

Volume of acetone = 257.4 mL

Explanation:

Density = mass / volume

Density Hg = Mass Hg / Volume Hg

13.59 g/mL = Mass Hg / 15 mL Hg

13.59 g/mL . 15 mL = Mass Hg → 203.85 g

This is the mass of acetone

Density acetone =  Mass acetone / Volume acetone

0.792 g/mL = 203.85 g / Volume of acetone

Volume of acetone = 203.85 g / 0.792 g/mL

Volume of acetone = 257.4 mL

3 0
3 years ago
Read 2 more answers
A 50.00 mL sample of groundwater is titrated with 0.0300 M EDTA . Of 12.40 mL of EDTA is required to titrate the 50.00 mL sample
Rzqust [24]

Answer:

7.44x10⁻³ mol/L and 744 ppm

Explanation:

Let's assume that the hardness of the water is totally from Ca⁺² ions only(the hardness is the measure of Ca⁺² and Mg⁺² ions). The titration with EDTA will form a complex. The EDTA is always in 1:1 proportion, so the number of moles of it will be the number of moles of Ca⁺², which will be the number of moles of CaCO₃.

n = 0.0124 L * 0.0300 mol/L

n = 3.72x10⁻⁴ mol

The molarity is the number of moles divided by the volume (0.05 L)

M = 3.72x10⁻⁴/0.05

M = 7.44x10⁻³ mol/L

1 part per million = 1 mg/L. The molar mass of the CaCO₃ is 100 g/mol, so the mass of it is:

m = 3.72x10⁻⁴ mol * 100 g/mol

m = 0.0372 g = 37.2 mg

Then, the ppm:

37.2/0.05 = 744 ppm

5 0
3 years ago
Biologists designed an experiment to test the effect of compost on the development of root crops. They tested several different
mars1129 [50]

Answer:

it is 56

Explanation:

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