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kozerog [31]
3 years ago
8

A chemist combine did 3.50g of potassium level with chlorine gas to yield 6.6 7g of potassium for it. Assuming all the potassium

was consumed, and that potassium chloride was the only product that formed, what mass of chlorine reacted?
Chemistry
1 answer:
slega [8]3 years ago
4 0

Answer: mass of chlorine reacted is 3.18 g

Explanation:

2 K + Cl2 = 2KCl

no. of moles of K = mass / molar mass

= 3.50 / 39

= 0.0897

no. of moles of KCl = mass / molar mass

= 6.67 / 74.5

= 0.0895  

no. of moles of Cl2 required = number of moles of KCl / 2

= 0.0895 / 2

= 0.0448 moles  

mass of Cl2 required = no. of moles of Cl2 required x molar mass

= 0.0448 x 71

= 3.1808 g ≈ 3.18 g

Therefore mass of chlorine reacted is 3.18 g

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Make the following conversions. Show your calculations.
Natalija [7]

Answer:

1. 500 cm = 5 m

2. 1000 g = 1 kg

3. 455 L = 45, 500 cL

4. 0.865 m = 0.00865 m or 8.65 * 10^-3 n

5. 33.5 cm = 335 mm

6. 0.0198 m = 19800 micrometers

7. 57.65 cg = 5.765 * 10^8 nanograms

8. 1000 L = 1 kl

9. 99 degrees F = 37.222 degrees C

Explanation:

1.  One meter = 100 centimeters

500 centimeters/ 100 centimeters = 5 meters

2. One kilogram = 1000 grams.

1000 grams/1000 grams = 1 kilogram

3. One Liter = 100 centiliters

455 liters * 100 centiliters = 45, 500 centiliters

4. One meter = 100 centimeters

0.865 centimeters/100 centimeters = 0.00865 meters

5. One centimeter = 10 millimeters

33.5 centimeters * 10 millimeters = 335 millimeters

6. One meter = 1.0 * 10^6 micrometers

0.0198 meters * 1 * 10^6 micrometers = 19800 micrometers.

7. One centigram = 1.0 * 10^7 nanograms

57.65 centigrams * 1 * 10^7 nanograms = 5.765 * 10^8 nanograms.

8. One kiloliter = 1000 L

1000 L/ 1000 L = 1 kiloliter

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So 5/9(99 - 32) = x

5/9(67) = x

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5 0
4 years ago
The change in direction of all free-moving objects ?
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A rigid 3.80 L sealed vessel contains 0.650 mol Ne, 0.321 mol Kr, and 0.190 mol Xe. Find the density of the mixture in g/L.
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Answer:

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Explanation:

Density = total mass of elements/ volume

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