Answer:
2, 6, 18, 54, 162
Step-by-step explanation:
In a geometric sequence, terms that are 2 terms apart (2nd & 4th, for example) have a ratio that is the 2nd power of the common ratio. Since 54/6 = 9 = 3², the common ratio is 3.
The first term will be the 2nd term divided by that ratio; the 5th term will be the 4th term multiplied by that ratio. You can figure the 3rd term any of several ways (and they should all give the same value): multiply the 2nd term, divide the 3rd term, or find the geometric mean of the 2nd & 4th terms: √(6·54) = 18.
Answer:
sorry if im wrong
Right circular cone
V=πr2h
3
Step-by-step explanation:
Answer:
A 125
Step-by-step explanation:
(40x4) +25
Answer:
B. 0
Step-by-step explanation:
2-2/5-2= 0/3= 0
Another way to look at this is that because they have the same y coordinate, it must simply be a horizontal line, which has a slope of 0
Answer:
(C) 50π
Step-by-step explanation:
For this problem, we need to find a way to relate the inner circle, to the square, to the outer circle.
Given that we know the area of a circle is πr^2, and our inner circle has a area of 25π, we can find the radius.
25π = πr^2
25 = r^2
5 = r
Note, that the diameter of the inner circle is parallel to the side of the square, meaning that the diameter of the inner circle is the length of the side of the square.
diameter = 2 * radius
d = 2 * 5 = 10.
Now that we know the value of the side of the square, we can find the length of the diagonal of the square, which is the diameter of the outer circle.
Using the properties of the 45-45-90 right triangle, we can say that the diagonal of the square is the length of the side times sqrt(2).
Outer_Diameter = 10 * sqrt(2)
Now to find the outer area, we need the formula for the area of a circle. Note that the diameter is twice the radius, so we will simply divide by 2.
A = πr^2
A = π * [ ( 10 * sqrt(2) ) / 2 ]^2
A = π * [ 5 * sqrt(2) ] ^2
A = π * 25 * 2
A = 50π
So the area of the outer circle is 50π.
Cheers.