Answer:
The answer to your question is given below below:
Explanation:
1. Data obtained from the question:
Concentration of Hydroxide ion, [OH-] = 1x10^-1 M
Concentration of Hydrogen ion, [H+] =..?
The concentration of Hydrogen ion and hydroxide ion are related with the following formula:
[H+] x [OH-] = 1x10^-14
[H+] x 1x10^-1 = 1x10^-14
Divide both side by 1x10^-1
[H+] = 1x10^-14 / 1x10^-1
[H+] = 1x10^-13M
2. Data obtained from the question include:
pH = 2
Hydrogen ion concentration, [H+] =..?
pH = - log [H+]
2 = - log [H+]
-2 = log [H+]
[H+] = antilog (-2)
[H+] = 0.01M
3. Data obtained from the question:
Concentration of Hydroxide ion, [OH-] = 1x10^-8 M
Concentration of Hydrogen ion, [H+] =..?
The concentration of Hydrogen ion and hydroxide ion are related with the following formula:
[H+] x [OH-] = 1x10^-14
[H+] x 1x10^-8 = 1x10^-14
Divide both side by 1x10^-8
[H+] = 1x10^-14 / 1x10^-8
[H+] = 1x10^-6M
4. Data obtained from the question include:
pOH = 9
Hydrogen ion concentration, [H+] =..?
First we shall determine the pH.
The pH and pOH are related with the following formula:
pH + pOH = 14
pH + 9 = 14
Collect like terms
pH = 14 - 9
pH = 5
Now, we can obtain the [H+] as follow:
pH = - log [H+]
pH = 5
5 = - log [H+]
-5 = log [H+]
[H+] = antilog (-5)
[H+] = 1x10^-5M
