Answer:
607 ppm
Explanation:
In this case we can start with the <u>ppm formula</u>:

If we have a solution of <u>0.0320 M</u>, we can say that in 1 L we have 0.032 mol of
, because the molarity formula is:

In other words:


If we use the <u>atomic mass</u> of
(19 g/mol) we can convert from mol to g:
Now we can <u>convert from g to mg</u> (1 g= 1000 mg), so:

Finally we can <u>divide by 1 L</u> to find the ppm:

<u>We will have a concentration of 607 ppm.</u>
I hope it helps!
Answer:
1. tropical storms and hurricanes
2.After a cold front moves through your area, you may notice that the temperature is cooler, the rain has stopped, and the cumulus clouds are replaced by stratus and stratocumulus clouds or clear skies.
3.Warm fronts often bring stormy weather as the warm air mass at the surface rises above the cool air mass, making clouds and storms. Warm fronts move more slowly than cold fronts because it is more difficult for the warm air to push the cold, dense air across the Earth's surface.
Explanation:
Answer:
Well, it could be B or D but I would say B.
Explanation:
The structure of an organelle is usually fit to its function so it is most likely B.
Hope this helps!
Answer:
½O 2 + 2e - + H 2O → 2OH.
Explanation:
Redox reactions - Higher
In terms of electrons:
oxidation is loss of electrons
reduction is gain of electrons
Rusting is a complex process. The example below show why both water and oxygen are needed for rusting to occur. They are interesting examples of oxidation, reduction and the use of half equations:
iron loses electrons and is oxidised to iron(II) ions: Fe → Fe2+ + 2e-
oxygen gains electrons in the presence of water and is reduced: ½O2 + 2e- + H2O → 2OH-
iron(II) ions lose electrons and are oxidised to iron(III) ions by oxygen: 2Fe2+ + ½O2 → 2Fe3+ + O2-
<span>a. x and y are atoms of the same element.
If both atoms contain the same amount of protons, they are always the same element.
</span>