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3 years ago

What is the source of all food energy on Earth?

Chemistry

2 answers:

Nuetrik [128]3 years ago

3 0

Answer:

C : producers

Explanation:

mart [117]3 years ago

3 0

I agree with what the person above said

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How many moles of H2s are produced when 2.25 moles Hcl react with excess zns

svlad2 [7]

Answer:

1.125 moles of H2S

Explanation:

From 2HCl(aq) + ZnS(s) ---------> H2S (g) + ZnCl2 (aq)

From the reaction equation;

2 moles of HCl produces 1 mole of H2S

Therefore 2.25 moles of HCl will produce 2.25 ×1/2 = 1.125 moles of H2S

Recall that it was explicitly stated in the question that ZnS is the reactant in excess. This implies that HCl is the limiting reactant and controls the amount of product obtained.

4 0

3 years ago

Air enters a diffuser witha velocity of 400 m/s, a pressure of 1 bar and temperature of 25 C. It exits with a temperature of 100

ANEK [815]

Answer:

Exit velocity of air is 96.43 m/s.

Explanation:

Given that

$V_1=400\ m/s$

$T_1=25C$

$T_2=100C$

For air

$C_p=1.005\ KJ/kg.K$

Now from first law of thermodynamics for open system at steady state

$h_1+\dfrac{V_1^2}{2000}+Q=h_2+\dfrac{V_2^2}{2000}+w$

For diffuser

$h_1+\dfrac{V_1^2}{2000}=h_2+\dfrac{V_2^2}{2000}$

We know that

$h=C_pT$

$h_1+\dfrac{V_1^2}{2}=h_2+\dfrac{V_2^2}{2000}$

$1.005\times 25+\dfrac{400^2}{2000}=1.005\times 100+\dfrac{V_2^2}{2}$

$V_2=96.43\ m/s$

So the exit velocity of air is 96.43 m/s.

8 0

4 years ago

Samuel tripped while playing basketball and skinned his knee on the concrete. Many of the skin cells on that knee were killed or

morpeh [17]

Answer:

D. Existing skin cells near the injury reproduced to make new cells.

8 0

3 years ago

Please answer this question pls

Luba_88 [7]

what's the question?

3 0

3 years ago

Read 2 more answers

Each cubic centimeter of gold has a mass of 19.3 g. A cube of gold measures 4.23 cm on each edge. (a) What is the volume of the

aivan3 [116]

Answer: The volume of the gold is $75.68g/cm^3$

The mass of gold is 19.3 g

The density of gold is $0.25g/cm^3$

Explanation:

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{Volume}$

Given : Mass of gold = 19.3 grams

To calculate the volume of cube, we use the equation:

$V=a^3$

where,

V = volume of cube

a = edge of cube

Volume of gold = $(4.23cm)^3=75.68cm^3$

Putting values in above equation, we get:

Putting in the values we get:

$Density=\frac{19.3g}{75.68cm^3}=0.25g/cm^3$

Thus density of gold will be $0.25g/cm^3$

4 0

3 years ago