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4 years ago

What are the mole ratios? 2 Mg +10, → 2 Mgo

Chemistry

1 answer:

Gala2k [10]4 years ago

6 0

Answer and explanation:

The mole ratio for Mg and MgO would be 2:2 or 1:1 because Mg has 2 as a coefficient and so does MgO, which is why you can simplify the ratio to 1:1

The mole ratio for O and MgO would be 1:2 because O has 1 as the coefficient and MgO has 2 as a coefficient.

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Which process is suitable for obtaining the water from an aqueous solution of sugar?

hoa [83]

Answer is: distillation.

Solution of sugar and water has a uniform composition and is able to be separated by physical means.

Solution is homogeneous mixture has the same proporties of its components throughout any given sample.

Solution of water and salt, can be separated with distillation (process of heating and cooling). Water evaporates and sugar remain in the beaker.

3 0

3 years ago

Naming Compounds Test Review Practice Name the following ionic compounds: NH4Cl _____________________________________ Fe(NO3)3 _

Mariulka [41]

Answer :

The name of $NH_4Cl$ is ammonium chloride.

The name of $Fe(NO_3)_3$ is iron(III) nitrate.

The name of $TiBr_3$ is titanium(III) bromide.

The name of $Cu_3P$ is copper(I) phosphide.

The name of $SnSe_2$ is tin(IV) selenide.

The name of $GaAs$ is gallium arsenide.

The name of $Pb(SO_4)_2$ is lead(IV) sulfate.

The name of $Be(HCO_3)_2$ is beryllium hydrogen carbonate.

The name of $Mn_2(SO_3)_3$ is manganese(III) sulfite.

The name of $Al(CN)_3$ is aluminium cyanide.

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The nomenclature of ionic compounds is given by:

1. Positive is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.

(a) $NH_4Cl$

It is an ionic compound because it is formed by the combination of one polyatomic cation (ammonium ion) and anion (chloride ion). The charge on ammonium ion is (+1) and the the charge on chloride ion is (-1).

Thus, the name of $NH_4Cl$ is ammonium chloride.

(b) $Fe(NO_3)_3$

It is an ionic compound because it is formed by the combination of one polyatomic anion (nitrate ion) and cation (iron ion). The charge on iron ion is (+3) and the the charge on nitrate ion is (-1).

Thus, the name of $Fe(NO_3)_3$ is iron(III) nitrate.

(c) $TiBr_3$

It is an ionic compound because it is formed by the combination of titanium cation and bromide anion. The charge on titanium is (+3) and the the charge on bromide ion is (-1).

Thus, the name of $TiBr_3$ is titanium(III) bromide.

(d) $Cu_3P$

It is an ionic compound because it is formed by the combination of copper cation and phosphorous anion. The charge on copper is (+1) and the the charge on phosphorous ion is (-3).

Thus, the name of $Cu_3P$ is copper(I) phosphide.

(e) $SnSe_2$

It is an ionic compound because it is formed by the combination of tin cation and selenium anion. The charge on tin is (+4) and the the charge on selenium ion is (-2).

Thus, the name of $SnSe_2$ is tin(IV) selenide.

(f) $GaAs$

It is an ionic compound because it is formed by the combination of gallium cation and arsenic anion. The charge on gallium is (+3) and the the charge on arsenic ion is (-3).

Thus, the name of $GaAs$ is gallium arsenide.

(g) $Pb(SO_4)_2$

It is an ionic compound because it is formed by the combination of one polyatomic anion (sulfate ion) and cation (lead ion). The charge on lead ion is (+4) and the the charge on sulfate ion is (-2).

Thus, the name of $Pb(SO_4)_2$ is lead(IV) sulfate.

(h) $Be(HCO_3)_2$

It is an ionic compound because it is formed by the combination of one polyatomic anion (hydrogen carbonate ion) and cation (beryllium ion). The charge on beryllium ion is (+2) and the the charge on hydrogen carbonate ion is (-1).

Thus, the name of $Be(HCO_3)_2$ is beryllium hydrogen carbonate.

(i) $Mn_2(SO_3)_3$

It is an ionic compound because it is formed by the combination of one polyatomic anion (sulfite ion) and cation (manganese ion). The charge on manganese ion is (+3) and the the charge on sulfite ion is (-2).

Thus, the name of $Mn_2(SO_3)_3$ is manganese(III) sulfite.

(j) $Al(CN)_3$

It is an ionic compound because it is formed by the combination of one polyatomic anion (cyanide ion) and cation (aluminium ion). The charge on aluminium ion is (+3) and the the charge on cyanide ion is (-1).

Thus, the name of $Al(CN)_3$ is aluminium cyanide.

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3 years ago

Which statement describes magnetic force?

tekilochka [14]

Answer:

D. A north pole and south pole attract each other

6 0

3 years ago

What describes how the bond between two oxygen atoms is formed

HACTEHA [7]

The bond that exist between two oxygen atoms is called a double covalent bond. This bond involves the sharing of four electrons to obtain a more stable structure. This type of bond is much stronger than the single covalent bond. They are much harder to break.

4 0

4 years ago

What is the maximum mass of ammonia that can be formed when 36.52 grams of nitrogen gas reacts with 10.62 grams of hydrogen gas

k0ka [10]

The maximum mass of NH₃ that can be formed when 36.52 g of N₂ reacts with 10.62 g of H₂ is 44.35 g

<h3>Balanced equation </h3>

N₂ + 3H₂ —> 2NH₃

Molar mass of N₂ = 14 × 2 = 28 g/mol

Mass of N₂ from the balanced equation = 1 × 28 = 28 g

Molar mass of H₂ = 2 × 1 = 2 g/mol

Mass of H₂ from the balanced equation = 3 × 2 = 6 g

Molar mass of NH₃ = 14 + (3×1) = 17 g/mol

Mass of NH₃ from the balanced equation = 2 × 17 = 34 g

SUMMARY

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂ to produce 34 g of NH₃

<h3>How to determine the limiting reactant </h3>

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

36.52 g of N₂ will react with = (36.52 × 6) / 28 = 7.83 g of H₂

From the above calculation, we can see that only 7.83 g out of 10.62 g of H₂ are required to react completely with 36.52 g of N₂.

Therefore, N₂ is the limiting reactant

<h3>How to determine the maximum mass of NH₃ produced </h3>

From the balanced equation above,

28 g of N₂ reacted to produce 34 g of NH₃

Therefore,

36.52 g of N₂ will react to produce = (36.52 × 34) / 28 = 44.35 g of NH₃

Thus, the maximum mass of NH₃ obtained from the reaction is 44.35 g

Learn more about stoichiometry:

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4 0

2 years ago