Answer:
a. What makes this an oxidation-reduction reaction? (1 point)
Loss of electron by the aluminum and the gain of electron by the silver
b. Write the half-reactions showing the oxidation and reduction reactions. Identify which is the oxidation reaction and which is the reduction reaction. (3 points)
oxidation half reaction: Al → Al3+ + 3e-
Reduction half reaction: Ag+ + e- → Ag
c. What is oxidized in the reaction? What is reduced? (2 points)
Aluminum is oxidized and silver is reduced
d. In this simple electrochemical cell, what functions as the anode? What is the cathode? (3 points)
In a simple electrochemical cell the electrode where oxidation takes place is the anode. And the electrode where reduction reaction happens is the cathode.
e. Is this a galvanic cell or electrolytic cell? Explain your answer. (2 points)
An electrolytic cell because the reaction converts electrical energy into chemical energy
Not sure about e and f!
What are you trying to find out?
<span>(15.0 g) / (150.0 g) x (100 g) = 10.0 g/100 g H2O </span>
Calculating K from Known Initial Amounts and the Known Change in Amount of One of the Species<span>Write the equilibrium expression for the reaction.Determine the molar concentrations or partial pressures of each species involved.<span>Determine all equilibrium concentrations or partial pressures using an ICE chart.</span></span>
