To find f'(3) (f prime of 3), you must find f' first. f' is the derivative of the function f(x).
Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.
The power rule for derivatives is ![\frac{d}{dx} [x^{n} ] =nx^{n-1}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bx%5E%7Bn%7D%20%5D%20%3Dnx%5E%7Bn-1%7D)
. In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.
f'(x) = 
(2x⁴)
f'(x) = 2(4)x³
f'(x) = 8x³
Now, to find f'(3), plug 3 into your derivative.
f'(3) = 8(3)³
f'(3) = 216
<h3>Answer:</h3>
f'(3) = 216
Answer:
FV=PV(1−d)^n
FV = 290(1-.132)^14
FV = 290(.868)^14
FV = 39.96 g
Step-by-step explanation:
Answer:
B is the correct answer.
Step-by-step explanation:
graph attached below, with red as the parent function (f(x)=3^x) and blue as the change (f(x)=3^x-8).
Answer:
A.
Step-by-step explanation:
x^0=1 so you can cancel it out. when a number has a negavite exponent, you have to invert it. That means y^-6 goes at the denominator and becomes y^6 and z^-6 goes up to the numerator and becomes z^6.
Answer:
Answer is on pic
Step-by-step explanation:
I hope it's helpful!
