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3 years ago

How can you solve problems by ordering rational numbers from least to greatest

Mathematics

1 answer:

SpyIntel [72]3 years ago

4 0

You can see what number they can go in to, or you can see what numbers are in the middle, first or last spots.

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A pool had 10 1/2 gallons of water in it Jake and his friend splashed g gallons of water out of the pool. There are 7 7/8 gallon

kolezko [41]

Answer: 6/625 gallons of water wa splashed out of the pool

Step-by-step explanation:

Total number of gallons of water in the pool was 10 1/2. Converting to improper fraction, it becomes

21/2 gallons.

Jake and his friend splashed g gallons of water out of the pool. There are 7 7/8 gallons still left in the pool. Converting 7 7/8 to improper fraction, it becomes

63/8 gallons

This means that

g + 63/8 = 21/2

g = 21/2 - 63/8 = (84 - 63)/8

g = 21/8 = 2.625 gallons

3 0

3 years ago

A nursery owner buys 5 panes of glass to fix some damage to her greenhouse. The 5 panes cost $12.25. Unfortunately, she breaks

Ksju [112]

Answer:

it would be $4.90

Step-by-step explanation:

12.25/5 is 2.45 per pane

4 0

2 years ago

Which of the following lines has a negative slope? <br> Is it Red<br> Is it Black<br> Is it Blue

Katena32 [7]

Answer:

black line <3

Step-by-step explanation:

the slope is -2 :)

3 0

2 years ago

Read 2 more answers

If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal

lorasvet [3.4K]

Answer:

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

The probability is $P(Z > 2.5 ) = 0.0062097$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 800$

The variance is $var(x) = 1600 \ kg$

The range consider is $x_1 = 778 \ kg \ x_2 = 834 \ kg$

The value consider in second question is $x = 900 \ kg$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{var (x)}$

substituting value

$\sigma = \sqrt{1600}$

$\sigma = 40$

The percentage of a cucumber give the crop amount between 778 and 834 kg is mathematically represented as

$P(x_1 < X < x_2 ) = P( \frac{x_1 - \mu }{\sigma} < \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma } )$

Generally $\frac{X - \mu }{ \sigma } = Z (standardized \ value \ of \ X)$

$P(x_1 < X < x_2 ) = P( \frac{778 - 800 }{40} < Z< \frac{834 - 800 }{40 } )$

$P(x_1 < X < x_2 ) = P(z_2 < 0.85) - P(z_1 < -0.55)$

From the z-table the value for $P(z_1 < 0.85) = 0.80234$

and $P(z_1 < -0.55) = 0.29116$

$P(x_1 < X < x_2 ) = 0.80234 - 0.29116$

$P(x_1 < X < x_2 ) = 0.51118$

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

$P(X > x ) = P(\frac{X - \mu }{\sigma } > \frac{x - \mu }{\sigma } )$

substituting values

$P(X > x ) = P( \frac{X - \mu }{\sigma } >\frac{900 - 800 }{40 } )$

$P(X > x ) = P(Z >2.5 )$

From the z-table the value for $P(Z > 2.5 ) = 0.0062097$

7 0

3 years ago

Does anyone know #4?

Marta_Voda [28]

The state should charge rain tax for businesses that cause most environmental damage due to runoff from their paved areas

7 0

2 years ago