Answer: Electrostatic force of attraction
Explanation: Electrostatic force of attraction is the force of attraction or repulsion between two electrically charged particles at rest. Like charges repel and unlike charges attract each other.
The magnitude of a vertical electric field that will balance the weight of a plastic sphere of mass 2. 1 g that has been charged to -3. 0 NC is 6.86 ×
N/C.
An electric field is the physical field that surrounds electrically charged particles and exerts a force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field of a system of charged particles.
It is given that,
Mass of sphere, m = 2.1 g =0.0021kg
Charge,q = ₋3nC = ₋ 3 ₓ 
To balance the weight of a plastic sphere, we must determine the magnitude of the electric field. So,

a = g

E = 
E = 6860000 N/C
E = 6.86 ×
N/C
Hence, the magnitude of the electric field that balances its weight is 6.86 ×
N/C .
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The volume of the cylinder is:
V= pi* (r^2) * h.
So the volume is = pi * (5.7/2)^2 * 12 = 306.2 in^2.
Since it is scaled up by the factor of 1.5, so we have to multiply each dimension with 1.5.
That means the diameter will be 8.55 and the height will be 18. so the scaled up volume will be
=pi * ((5.7*1.5)/2)^2 * (12*1.5)
The answer then would have to be 1033.5
Answer:
С. 30 m
Explanation:
Given the following data;
Initial velocity, U = 12m/s
Final velocity, V = 18m/s
Acceleration, a = 3m/s²
To find the distance, we would use the third equation of motion;
V ² = U² + 2aS
Substituting into the equation, we have
18² = 12² + 2*3*S
324 = 144 + 6S
6S = 324 - 144
6S = 180
S = 180/6
Distance, S = 30 meters.