Question

What is the magnitude of a the vertical electric field that will balance the weight of a plastic sphere of mass 2. 1 g that has been charged to -3. 0 nc? (k = 1/4πε0 = 9. 0 × 109 n ∙ m2/c2)

Answer 1

The magnitude of a vertical electric field that will balance the weight of a plastic sphere of mass 2. 1 g that has been charged to -3. 0 NC is 6.86 × $10^{6}$ N/C.

An electric field is the physical field that surrounds electrically charged particles and exerts a force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field of a system of charged particles.

It is given that,

Mass of sphere, m = 2.1 g =0.0021kg

Charge,q = ₋3nC = ₋ 3 ₓ $10^{-9}$

To balance the weight of a plastic sphere, we must determine the magnitude of the electric field. So,

$ma= qE$

a = g

$E = \frac{mg}{q}$

E = $\frac{0.0021 * 9.8}{-3 * 10^{-9} }$

E = 6860000 N/C

E = 6.86 × $10^{6}$ N/C

Hence, the magnitude of the electric field that balances its weight is 6.86 × $10^{6}$ N/C .

To know more about  electric field refer to:  brainly.com/question/8971780

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