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Andru [333]
2 years ago
7

What is the magnitude of a the vertical electric field that will balance the weight of a plastic sphere of mass 2. 1 g that has

been charged to -3. 0 nc? (k = 1/4πε0 = 9. 0 × 109 n ∙ m2/c2)
Physics
1 answer:
sladkih [1.3K]2 years ago
5 0

The magnitude of a vertical electric field that will balance the weight of a plastic sphere of mass 2. 1 g that has been charged to -3. 0 NC is 6.86 × 10^{6} N/C.

An electric field is the physical field that surrounds electrically charged particles and exerts a force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field of a system of charged particles.

It is given that,

Mass of sphere, m = 2.1 g =0.0021kg

Charge,q = ₋3nC = ₋ 3 ₓ 10^{-9}

To balance the weight of a plastic sphere, we must determine the magnitude of the electric field. So,

ma= qE

a = g

E = \frac{mg}{q}

E = \frac{0.0021 * 9.8}{-3 * 10^{-9} }

E = 6860000 N/C

E = 6.86 × 10^{6} N/C

Hence, the magnitude of the electric field that balances its weight is 6.86 × 10^{6} N/C .

To know more about  electric field refer to:  brainly.com/question/8971780

#SPJ4

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