The correct answer among the choices above is option C. <span>Beryllium, Be, and chlorine, Cl, form a binary ionic compound with a one-to-two ratio of beryllium ions to chloride ions.</span> The chemical formula for the compound of beryllium and chlorine is BeCl2.
Answer:
Acceleration = 9.8 m/sec2
Explanation:
We know that the acceleration due to gravity is 9.8 m/sec2 near the surface of earth.
Remember that the gravity is always affecting everything on earth at every instant, even the rock at the very top of it's trajectory. It doesn't mind if the velocity is zero for an instant or if there's air resistance, the gravity force is there, and always aims towards the center of the earth.
So for all the trajectory of the rock, gravity is 9.8 m/sec2
Answer:
I would say it is recycling nonrenewable minerals instead of throwing them away.
Explanation:
using grocery bags only once before disposing them is also bad, but plastic is not really a resource compared to how minerals are resources.
if we recycle nonrenewable resources instead of throwing them away we would damage true resources.
Answer:
-12.38 N
Explanation:
This question requires you to first find the acceleration then apply Newton's 2nd law of motion to find the force.
To find deceleration use the formula;
v²= u²+2ad ---where
v= final speed = 0 m/s
u= initial speed = 3.0 m/s
a= acceleration { in this case , deceleration} = ?
d= distance from the point where its passenger rolled off= 4.0 m
therefore ;
Mass of the sled is calculated from its weight force.
Weight force = mg
mass of sled = weight force / g where g= 10 m/s²
mass of sled = 110/10 = 11kg
The magnitude of horizontal net force will be : F= ma where ;
m= mass of sled = 11 kg
a= deceleration = -9/8 m/s²
F = 11 * -9/8 = -12.38 N
Force is acting on the opposite direction of the initial motion of the sled.
Answer:
E = 2.17 x 10⁻² V/m
Explanation:
First we will find out the current density by using the formula:
J = I/A
where.
J = Current Density = ?
I = Current = 5.5 A
A = Cross-Sectional Area = πr² = π(1.5 x 10⁻³ m)² = 7.068 x 10⁻⁶ m²
Therefore,
J = 5.5 A/7.068 x 10⁻⁶ m²
J = 0.778 x 10⁶ A/m²
Now, we calculate the magnitude of applied field:
E = ρJ
where,
E = Magnitude of applied field = ?
ρ = resistivity of Aluminum = 2.8 x 10⁻⁸ Ω.m
Therefore,
E = (2.8 x 10⁻⁸ Ω.m)(0.778 x 10⁶ A/m²)
<u>E = 2.17 x 10⁻² V/m</u>