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ANTONII [103]
3 years ago
11

A soccer ball is kicked and left the ground at angle 45° above the horizantal, moving at 25 m/s.

Physics
1 answer:
Tcecarenko [31]3 years ago
8 0

Answer:

a) 3.6 sec

b) 17.7 m/s

c) 17.7 m/s

d) 63.6 m

Explanation:

y = (25sin45)t - 4.9t^2 =17.7t - 4.9t^2

a) to find hang time set y = 0

4.9t^2 = 17.7t or t = 3.6 sec

b) vx = 25cos45 = 17.7 m/s

c) vy = 25sin45 = 17.7 m/s

d) To find the range R, use the results in (a) and (b) into the equation R = vxt:

R = (17.7 m/s)(3.6 sec) = 63.6 m

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A ball with an initial velocity of 12 m/s is rolling up a hill. The ball accelerates at a rate of -2.6 m/s/s.
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Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.23 2.23 times a second. A tack is stuck in the t
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Explanation:

The given data is as follows.

       Angular velocity (\omega) = 2.23 rps

     Distance from the center (R) = 0.379 m

First, we will convert revolutions per second into radian per second as follows.

             = 2.23 revolutions per second

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Now, tangential speed will be calculated as follows.

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