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Darya [45]
3 years ago
7

A toy store sells either small dolls or large dolls. If one person buys 6 small dolls and 5 large dolls and spends $65, and anot

her person buys 5 small dolls and 4 large dolls and spends $53, how much does each type of dolls cost?
Mathematics
2 answers:
VARVARA [1.3K]3 years ago
7 0
6 small dolls + 5 large dolls = $65<em> ------------------ (1) </em>
5 small dolls + 4 large dolls = $53 <em>------------------ (2)</em>

<em>(1) x 5 : </em>30 small dolls + 25 large dolls = $325<span> <em>------------------ (1a)</em></span><em> </em>
<em>(2) x 6 : </em>30 small dolls + 24 large dolls = $318<em> ------------------ (2a)</em>

<em>(1a) - (2a) :</em> 1 large doll = $7

<em>Substitute 1 large doll = $7 into (1):</em>

6 small dolls + 5(7)  = $65
6 small dolls + 35  = $65
6 small dolls = $65 - $35
6 small dolls = $30
1 small doll  = $5

Answer: 1 small doll is $5 and I large doll is $7.




FrozenT [24]3 years ago
5 0
Each small doll cost 6.5 dollars and each large doll cost 10 dollars
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<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:                                                              

\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C

Integration Property [Multiplied Constant]:                                                        

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Integration Property [Addition/Subtraction]:                                                      

\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx    -\int 2dx          

[Integrals] Rewrite [Integration Property - Multiplied Constant]:  

\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx    -2\int dx            

[Integrals] Reverse Power Rule:    

\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C                                                            

Simplify:    

\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                                                                                                      

So the indefinite integral will be \int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                

To know more about indefinite integral follow

brainly.com/question/27419605

#SPJ4

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