I believe it is not that the red blood cell count goes down, but that the white blood cell count increases.
Not you coming on a homework helping app being desperate
Answer:
the total distance moved by the wave from it's equilibrium point.
Explanation:
I picture the equivalent as standing on the floor is equilibrium point or starting. how high you jump is your amplitude.
✦ ✦ ✦ Beep Boop - Blu Bot! At Your Service! Scanning Question . . . Code :
Green! Letters and Variables Received! ✦ ✦ ✦
--------------------------------------------------------------------------------------------------------------
Answer:
The entropy of a substance can be obtained by measuring the heat required to raise the temperature a given amount, using a reversible process . The standard molar entropy, So, is the entropy of 1 mole of a substance in its standard state, at 1 atm of pressure. (Below are listed tips)
- At absolute zero (0 K), the entropy of a pure, perfect crystal is zero.
- The entropy of a substance can be obtained by measuring the heat required to raise the temperature a given amount, using a reversible process.
- The standard molar entropy, So, is the entropy of 1 mole of a substance in its standard state, at 1 atm of pressure.
--------------------------------------------------------------------------------------------------------------
- NH₃: Hydrogen bonds;
- CCl₄: London Dispersion Forces; (a.k.a. Induced dipole)
- HCl: Dipole-dipole Interactions.
<h3>Explanation</h3>
Relative strength of intermolecular forces in small molecules:
Hydrogen bonds > Dipole-dipole interactions > London DIspersion Forces.
It takes two conditions for molecules in a substance to form <em>hydrogen bonds</em>.
- They shall contain at least one of the three bonds: H-F, O-H, or N-H.
- They shall contain at least one lone pair of electrons.
NH₃ contains N-H bonds. The central nitrogen atom in an NH₃ molecule has one lone pair of electrons. NH₃ meets both conditions; it is capable of forming hydrogen bonds.
CCl₄ molecules are nonpolar. The molecule has a tetrahedral geometry. Dipole from the polar C-Cl bonds cancel out due to symmetry. The molecule is nonpolar overall. As a result, only London Dispersion Force is possible between CCl₄ molecules.
HCl molecules are polar. The H-Cl bond is fairly polar. The HCl molecule is asymmetric, such that the dipole won't cancel out. The molecule is overall polar. Both dipole-dipole interactions and London Dispersion Force are possible between HCl molecules. However, dipole-dipole interactions are most predominant among the two.
