<span>
Sodium Oxide= Na2O
The formula mass of Na2O is (2x23) + 16 = 62g/mol
% Na= (46/62) x 100 = 74%
% O= (16/62) x 100 = 26%</span><span>
</span>
Answer:
pH = 12.52
Explanation:
Given that,
The [H+] concentration is
.
We need to find its pH.
We know that, the definition of pH is as follows :
![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
Put all the values,
![pH=-log[3\times 10^{-13}]\\\\pH=12.52](https://tex.z-dn.net/?f=pH%3D-log%5B3%5Ctimes%2010%5E%7B-13%7D%5D%5C%5C%5C%5CpH%3D12.52)
So, the pH is 12.52.
There are 2.32 x 10^6 kg sulfuric acid in the rainfall.
Solution:
We can find the volume of the solution by the product of 1.00 in and 1800 miles2:
1800 miles2 * 2.59e+6 sq m / 1 sq mi = 4.662 x 10^9 sq m
1.00 in * 1 m / 39.3701 in = 0.0254 m
Volume = 4.662 x 10^9 m^2 * 0.0254 m
= 1.184 x 10^8 m^3 * 1000 L / 1 m3
= 1.184 x 10^11 Liters
We get the molarity of H2SO4 from the concentration of [H+] given by pH = 3.70:
[H+] = 10^-pH = 10^-3.7 = 0.000200 M
[H2SO4] = 0.000100 M
By multiplying the molarity of sulfuric acid by the volume of the solution, we can get the number of moles of sulfuric acid:
1.184 x 10^11 L * 0.000100 mol/L H2SO4 = 2.36 x 10^7 moles H2SO4
We can now calculate for the mass of sulfuric acid in the rainfall:
mass of H2SO4 = 2.36 x 10^7 moles * 98.079 g/mol
= 2.32 x 10^9 g * 1 kg / 1000 g
= 2.32 x 10^6 kg H2SO4
The arrangement of the solutions based on their absorption from highest frequency to lowest frequency :
b.
> c.
> a.NaCl
<h3>What is absorption frequency?</h3>
- The frequency of the molecular vibration that led to the absorption is the same as the absorption frequency of a basic IR absorption band.
- In a way, an emission spectrum is the opposite of an absorption spectrum.
- The discrepancies in the energy levels of each chemical element's orbitals correspond to absorption lines for each chemical element at various particular wavelengths.
- Therefore, it is possible to identify the constituents in a gas or liquid using its absorption spectrum.
- Absorption spectroscopy is most frequently used to measure infrared, atomic, visible, ultraviolet (UV), and x-ray waves.
Learn more about Absorption frequency here:
brainly.com/question/5032775
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Answer:
These particles were considered so small that they were unable to be cut