Now molecules: ____ molecules of H2 + ____ molecules of O2 → ___

Bromine has a density of 3.10g/cm3. If you have 50.0 ML of bromine, how many grams do you have?

Zanzabum

Answer:

The answer is

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of bromine = 50 mL

density = 3.10 g/cm³

It's mass is

mass = 50 × 3.10

We have the final answer as

Hope this<u> </u>helps you

5 0

3 years ago

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Anyone here im getting bored feel

xxTIMURxx [149]

Yeah im here and i am alos getting bored to

what are you doing and how is your day ?

5 0

3 years ago

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Write and balance the equation for the combination of ammonia gas with solid copper (II) oxide to produce copper metal, nitrogen

Katena32 [7]

Explanation :

The balanced chemical reaction will be,

$3CuO(s)+2NH_3(g)\rightarrow 3Cu(s)+N_2(g)+3H_2O(l)$

By the stiochiometry, 3 moles of solid copper(II)oxide react with 2 moles of ammonia gas to give 3 moles of copper metal, 1 mole of nitrogen gas and 3 moles of liquid water.

The states of matter of each elements and compound is,

Copper(II)oxide is in solid state

Ammonia is in gaseous state

Copper metal is in solid state

Nitrogen is in gaseous state

Water is in liquid state

7 0

3 years ago

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. Though Florida receives a lot of rainfall, only 1 percent remains available for people to use or drink. What happens to the re

monitta

1st part.)). The rest of the water goes into oceans and underground.

8 0

3 years ago

A gas-filled weather balloon with a volume of 65.0 L is released at sea level where conditions are745 torr and 25 ºC. The balloo

Blababa [14]

Answer:

It will reach to its maximum volume.

Explanation:

Using Ideal gas equation for same mole of gas as :-

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 65.0 mL

V₂ = ?

P₁ = 745 torr

The conversion of P(torr) to P(atm) is shown below:

$P(torr)=\frac {1}{760}\times P(atm)$

So,

Pressure = 745 / 760 atm = 0.9803 atm

P₁ = 0.9803 atm

P₂ = 0.066 atm

T₁ = 25 ºC

T₂ = -5 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (25 + 273.15) K = 298.15 K

T₂ = (-5 + 273.15) K = 268.15 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{0.9803}\times {65.0}}{298.15}=\frac{{0.066}\times {V_2}}{268.15}$

Solving for V₂ as:-

$V_2=\frac{0.9803\times \:65.0\times 268.15}{298.15\times 0.066}$

$V_2=\frac{17086.38392}{19.6779}$

V₂ = 868 L

Given that:- V max = 835 L

<u>Thus, it will reach to its maximum volume.</u>

3 0

3 years ago

Now molecules: ____ molecules of H2 + ____ molecules of O2 → ____molecules of H2O

Now molecules: molecules of H2 + molecules of O2 → molecules of H2O