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kondaur [170]
3 years ago
14

Timed please help :))

Mathematics
1 answer:
Sphinxa [80]3 years ago
3 0

It's the first one :))

You might be interested in
Find the quotient of 68.0052 and 12. Round your answer to the nearest hundredth
Vlad1618 [11]
68.01
A quotient is the answer to two numbers being divided.
Meaning 68.0052÷12 is 68.01
8 0
4 years ago
Suppose that AB and EF are corresponding sides of similar triangles. If AB=2 and the scale factor is 5, what is EF?
Zina [86]

Answer:

EF=10

Step-by-step explanation:

If they are corresponding,

AB = 2 x Scale factor of 5 = 10

8 0
3 years ago
On 1 May 2012, the cost of 5 grams of gold was 14 000 rupees.
navik [9.2K]

Answer:

51,800 rupees

Step-by-step explanation:

Cost of 5 grams of gold on 1 May 2012 = 14 000 rupees.

The cost of gold decreased by 7.5% from 1 May 2012 to 1 May 2013

Cost of 5 grams of gold on 1 May 2013 = 14,000 - 7.5% of 14,000

= 14,000 - 0.075 × 14,000

= 14,000 - 1,050

= 12,950 rupees

Work out the cost of 20 grams of gold on 1 May 2013

Since, there are four 5 grams of gold in 20 grams of gold

Therefore,

Cost of 20 grams of gold on 1 May 2013 = 12,950 rupees × 4

= 51,800 rupees

4 0
3 years ago
Given AG bisects CD, IJ bisects CE, and BH bisects ED. Prove KE = FD.
OverLord2011 [107]

When a line is bisected, the line is divided into equal halves.

See below for the proof of \mathbf{KE \cong FD}

The given parameters are:

  • <em>AC bisects CD</em>
  • <em>IJ bisects CE</em>
  • <em>BH bisects ED</em>

<em />

By definition of segment bisection, we have:

  • \mathbf{CK \cong KE}
  • \mathbf{EF \cong FD}
  • \mathbf{CE \cong ED}

By definition of congruent segments, the above congruence equations become:

  • \mathbf{CK = KE}
  • \mathbf{EF = FD}
  • \mathbf{CE = ED}

By segment addition postulate, we have:

  • \mathbf{CE = CK + KE}
  • \mathbf{ED = EF + FD}

Substitute \mathbf{ED = EF + FD} in \mathbf{CE = ED}

\mathbf{CK + KE = EF + FD}

Substitute \mathbf{CK = KE} and \mathbf{EF = FD}

\mathbf{KE + KE = FD + FD}

Simplify

\mathbf{2KE = 2FD}

Apply division property of equality

\mathbf{KE = FD}

By definition of congruent segments

\mathbf{KE \cong FD}

Read more about proofs of congruent segments at:

brainly.com/question/11494126

6 0
3 years ago
Find the values of x and y that make the following quadrilateral a parallelogram.
lidiya [134]

Answer:

x = 3 and y = 14

Step-by-step explanation:

opposite angles of a parallelogram are congruent. Hence,

1) 7y + 2 = 6y + 16

I. e. 7y - 6y = 16 - 2

I. e. y = 14

2) 8x + 8 = 6x + 14

I. e. 8x - 6x = 14 - 8

I. e. 2x = 6

I. e. x = 6/2

I. e. x = 3

7 0
3 years ago
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