<u>16/27 is </u><u>the value of </u><u>quantity</u><u>.</u>
What is a linear equation in math?
- A linear equation only has one or two variables. No variable in a linear equation is raised to a power greater than 1 or used as the denominator of a fraction.
- When you find pairs of values that make a linear equation true and plot those pairs on a coordinate grid, all of the points lie on the same line.
- There are three major forms of linear equations: point-slope form, standard form, and slope-intercept form. We review all three in this article.
- Some of the examples of linear equations are 2x – 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, x + y = 2, 3x – y + z = 3.
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Step 1) You would need to convert your 2 fractions into equivalent numbers. In this case, the closet gcf (greatest common factor) is 12. So, 5/4 would convert to 15/12 and 2/3 converts to 8/12.
Step 2) You know have your decimals that are equivalent. All you have left now is to subtract. Take 15/12 and subtract 8/12 from it. You would now get 7/12 of a mile that is still needed to run.
Step 3) Usually, you would simplify your new fraction. In this case, our fraction doesn't simplify. It will stay 7/12 of a mile. For example, If our number had ended up being 4/12, then we would simplify it to 1/3 of a mile. Because, 4 divided by 4 is 1 and 12 divided by 4 is 3. You can't simplify your answer anymore.
Hope this helped!
Answer:
A) (-9/7,0), (3/8,0)
Step-by-step explanation:
Zeros of a quadratic function:
x for which y = 0.
In this question:
It's 0 if one of the factors is 0. 6 is never 0, now about the other to:
So (-9/7, 0) is a zero of the quadratic function.
The other is:
(3/8,0) is the other zero.
Thus, the correct answer is given by option A.
V=V of cube- V pyramid= 8^3- 7^2*8/3=512-49*8/3=512-130,67=381.33 cm^3
The solution to the given differential equation is yp=−14xcos(2x)
The characteristic equation for this differential equation is:
P(s)=s2+4
The roots of the characteristic equation are:
s=±2i
Therefore, the homogeneous solution is:
yh=c1sin(2x)+c2cos(2x)
Notice that the forcing function has the same angular frequency as the homogeneous solution. In this case, we have resonance. The particular solution will have the form:
yp=Axsin(2x)+Bxcos(2x)
If you take the second derivative of the equation above for yp , and then substitute that result, y′′p , along with equation for yp above, into the left-hand side of the original differential equation, and then simultaneously solve for the values of A and B that make the left-hand side of the differential equation equal to the forcing function on the right-hand side, sin(2x) , you will find:
A=0
B=−14
Therefore,
yp=−14xcos(2x)
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