When A is reflected over y=-1, -1+(-1-(-2))=0, it lands on (-5, 0), when it is then reflected over x=3, 3+(3-(-5))=11, it lands on (11,0)
If you can't visualize it, draw a graph.
Answer:
The correct option is D.
Step-by-step explanation:
The given graph is the graph of a cosine function, which shifts 1 unit left.
The cosine function is defined as
Where, a is amplitude, b is frequency, c is phase shift and d is vertical shift.
If c>0, then the graph shifts c units left and if c<0, then the graph shifts c units right.
Since the graph show only phase shift and the graph shifts only one unit left, therefore required function is
Option D is correct.
Answer:
Step-by-step explanation:
We can find the slope through two points.
m = (y2 - y1)/(x2 - x1)
m = (4 - -5)/(4 - -8)
m = 9/12 = 3/4
The slope of the line is 3/4.
Slope-intercept form of a line is y=mx+b. Where m is the slope and b is the y-intercept.
y = 3/4x + b
A point on the line is (4, 4). x = 4 and y =4.
4 = 3/4(4) + b
4 = 3 + b
b = 1
The y-intercept is 1.
Answer:
c 81
Step-by-step explanation:
Answer:
6x
Step-by-step explanation:
3*2x=6x