Question

If 2 is added to both the numerator and denominator of a fraction its value becomes half. If two is subtracted from both the numerator and denominator of the same fraction its value becomes 1/3. What is the original fraction"

Answer 1

Answer:

The original fraction is $\frac{6}{14}$.

Step-by-step explanation:

Solution,

Let the fraction be'$\frac{x}{y}$'.

Where 'x' is the numerator and 'y' is the denominator.

Now according to question, if 2 is added to both the numerator and denominator the value of the fraction becomes 1/2.

So, framing the above sentence in equation form, we get;

$\frac{x+2}{y+2}=\frac{1}{2}$

On using cross multiplication method, we get;

$2(x+2)=y+2\\\\2x+4=y+2\\\\2x+4-2=y\\\\\therefore\ y=2x+2\ \ \ \ equation\ 1$

Now according to question, if 2 is Subtracted to both the numerator and denominator the value of the fraction becomes 1/3.

So, framing the above sentence in equation form, we get;

$\frac{x-2}{y-2}=\frac{1}{3}$

On using cross multiplication method, we get;

$3(x-2)=y-2\\\\3x-6=y-2\\\\3x-y=-2+6\\\\3x-y=4 \ \ \ \ equation\ 2$

Now Substituting the equation 1 in equation 1 we get;

$3x-y=4\\\\3x-(2x+2)=4\\\\3x-2x-2=4\\\\3x-2x=4+2\\\\x=6$

Now Substituting the value of x in equation 1 we get;

$y=2x+2\\\\y=2\times6+2 = 14$

Hence The original fraction is $\frac{6}{14}$.