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Y_Kistochka [10]
3 years ago
15

I need someone to talk to. Preferably a girl who is on around this time every day. Please

Mathematics
2 answers:
umka2103 [35]3 years ago
7 0
Um ok I'm on around this time everyday
Feliz [49]3 years ago
4 0
Hi :) hows it goin? on everydsy :)




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Which expression is equivalent to -3(4x-0.50)?<br> PLEASEEEEEEEEEEEEE HELPPP
Misha Larkins [42]

Final Answer: -12x + 1.5

Steps/Reasons/Explanation:

Question: Which expression is equivalent to -3(4x - 0.50)?

<u>Step 1</u>: Expand by distributing terms.

-3 × 4x - 3 × -0.50

<u>Step 2</u>: Simplify -3 × 4x to -12x.

-12x - 3 × -0.50

<u>Step 3</u>: Simplify 3 × -0.50 to -1.5.

-12x - (-1.5)

<u>Step 4</u>: Remove parentheses and add.

-12x + 1.5

~I hope I helped you :)~

6 0
3 years ago
Cheryl has $100 on her subway gift card. Each week she buys the same lunch for $10. She wants to continue using the card until t
ziro4ka [17]

Answer:

100-60=40

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Jillian bought 1/2 pound of turkey and 1 1/3 pounds of cheddar cheese at the store.both items are on sale $6 per pound.how much
olchik [2.2K]
10 dollars is ther answer
8 0
3 years ago
For the following right triangle find the side length x
sertanlavr [38]

Since there is a right angle, you can use Pythagoras' Theorem:

So x = √(24² + 7²) = 25

---------------------------------------------------------

Answer:

25

6 0
3 years ago
A) Model this situation with a linear system:
sergejj [24]

Answer:

The daily rate is $ 29 and the fee for each kilometer driven is $ 0.35.

Step-by-step explanation:

Since to rent a car, a person is charged a daily rate and a fee for each kilometer driven, and when Chena rented a car for 6 days and drove 320 km, the charge was $ 286.00, while when she rented the same car for 10 days and drove 900 km, the charge was $ 605.00, to determine the daily rate and the fee for each kilometer driven the following calculation must be performed:

286 = 6 days and 320 km

320/6 = 53,333 km

286/6 = $ 47,666

Thus, the value of 1 day and 53,333 km is $ 47,666.

605 = 10 days and 900 km

900/10 = 90 km

605/10 = $ 60.5

Thus, the value of 1 day and 90 km is $ 60.5.

90 - 53,333 = 36,666

60.5 - 47.666 = 12.833

12,833 / 36,666 = value per kilometer traveled

0.35 = value per kilometer traveled

(286 - (0.35 x 320)) / 6 = X

(286/112) / 6 = X

174/6 = X

29 = X

(605 - (0.35 x 900)) / 10 = X

(605 - 315) / 10 = X

290/10 = X

29 = X

Therefore, the daily rate is $ 29 and the fee for each kilometer driven is $ 0.35.

3 0
3 years ago
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